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Andrei [34K]
3 years ago
10

What is the blood resistivity if a 9.0 v potential difference causes a 210 μa current through the blood in the vein?

Physics
1 answer:
VLD [36.1K]3 years ago
5 0
<h3><u>Answer;</u></h3>

= 42,857.14 ohms.

<h3><u>Explanation;</u></h3>

According to ohm's Law; the current through a conductor is directly proportional to the potential difference at a constant temperature.

Therefore; V  I, thus; V = IR , Where R is the resistance.

Hence; Resistance, R = V/I

In this case;

Resistivity of column of blood = E/I

                                                  = 9/.00021,

                                                 <u>= 42,857.14 ohms.  </u>

                                                   

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If a questions says "at what point does the ball stop?" what is it asking for?
Bad White [126]

Explanation:

If a question says "at what point does the ball stop?", it means we need to find the position of the ball when its final velocity is equal to 0. It can be calculated using the equation of kinematics as follows :

d = ut + (1/2) at²

and

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5 0
3 years ago
Water is entering the prism at a rate of A m^3/hr. The prism is empty at time 0. Express the depth d of the water in meters in t
zavuch27 [327]

This question is incomplete, the complete question is;

The picture shows a triangular prism. The end of prism are equilateral triangles with x meters. the other dimension of the prism is L meters

a) Find the volume V in terms of x and L

b) Water is entering the prism at a rate of A m³/hr. The prism is empty at time 0. Express the depth d of the water in meters in terms of A, the length of time t the water has been entering the trough, and the length L of the prism.  

Answer:

a) the volume V in terms of x and L is  ((√3/4)x²L) m³

b) required expression is (2/(3)^(1/u))√(At/L)

Explanation:

Given that;

form the question and image below;

triangular prism ends are equilateral triangle

side length = x meter

Dimension of the prism = L meter

Area of the equilateral triangle = √3/4 (side)² = √3/4 (x)² meter

Volume of the triangular prism = Area × height

= √3/4 (x)² × L

V = ((√3/4)x²L) m³

Therefore, the volume V in terms of x and L is  ((√3/4)x²L) m³

b)

Rate of water entering = A m³/hr

Depth of water tank = d meter

Time = t

Length of prism = L

now Rate of water entering is A m³/hr

dv/d = A                             [  V = ((√3/4)x²L) m³ ]

and

dv/dt = √3/4 [2x dx/dt ] L                   { L is constant }

so

A = √3/4 [2x dx/dt ] L  

∫A dt = √3/2 [ Lx dx ]                   { Integrate both sides}

At = √3/2 × Lx × x²/2

x² = uAt / √3L                              { we find square root of both sides}

x = √( uAt / √3L )

x = (2/(3)^(1/u))√(At/L)

Therefore; required expression is (2/(3)^(1/u))√(At/L)

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Answer:

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\Delta p=12-(-12)=24\ kg-m/s

So, the change in momentum of the ball is 24 kg-m/s. Hence, this is the required solution.

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