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3 years ago

What is the blood resistivity if a 9.0 v potential difference causes a 210 μa current through the blood in the vein?

Physics

1 answer:

VLD [36.1K]3 years ago

5 0

<h3><u>Answer;</u></h3>

= 42,857.14 ohms.

<h3><u>Explanation;</u></h3>

According to ohm's Law; the current through a conductor is directly proportional to the potential difference at a constant temperature.

Therefore; V I, thus; V = IR , Where R is the resistance.

Hence; Resistance, R = V/I

In this case;

Resistivity of column of blood = E/I

= 9/.00021,

<u>= 42,857.14 ohms. </u>

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A traveler pulls on a suitcase strap at an angle 36 above the horizontal with a force of friction of 8 N with the floor. If 752

goldenfox [79]

Answer:

71.8 N

Explanation:

T = Tension force in the strap

W = net work done = 752 J

f = force of friction = 8 N

d = displacement = 15 m

θ = angle between tension force and horizontal displacement = 36 deg

work done by frictional force is given as

W' = - f d

Work done by the tension force is given as

W'' = T d Cos36

Net work done is given as

W = W' + W''

W = T d Cos36 - f d

752 = T (15) Cos36 - (8) (15)

T = 71.8 N

8 0

3 years ago

A certain material has a high melting point and is malleable and shiny. It is most likely a _____.

Sonbull [250]

The answer is metal

4 0

3 years ago

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Tyler stands at rest on a skateboard. He has a mass of 120 kg. His friend (m = 60 kg) jumps into his arms at a speed of 2 m/s. I

Andrews [41]

Momentum question. This is an inelastic collision, so

m1v1+m2v2=Vf(m1+m2)
Vf=(m1v1+m2v2)/(m1+m2)=[(120kg)(0m/s)+(60kg)(2m/s)] / (120kg+60kg)
Vf=120kg m/s / 180kg
Vf=0.67m/s

0.67m/s

5 0

4 years ago

A sealed test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18°C. The test tube’s stopper has a diamet

puteri [66]

Answer:

180° C

Explanation:

First we start by finding the area of the stopper.

A = πd²/4, where d = 1.5 cm = 0.015 m

A = 3.142 * 0.015² * ¼

A = 1.767*10^-4 m²

Next we find the force on the stopper

F = (P - P•)A, where

F = 10 N

P = pressure inside the tube,

P• = 1 atm

10 = (P - 101325) * 1.767*10^-4

P - 101325 = 10/1.767*10^-4

P - 101325 = 56593

P = 56593 + 101325

P = 157918 Pascal

Now, remember, in an ideal gas,

P1V1/T1 = P2V2/T2, where V is constant, then we have

P1/T1 = P2/T2, and when we substitute the values, we have

101325/(273 + 18) = 157918/ T2

101325/291 = 157918/ T2

T2 = (157918 * 291)/101325

T2 = 453 K

T2 = 453 - 273 = 180° C

3 0

4 years ago

What can increase the peak emf in an ac generator without changing the frequency?

STatiana [176]

Explanation:

The peak emf in an AC generator is given by :

$\epsilon=NAB\omega$

Here,

N is number of turns in the generator

A is area of the coils

B is magnetic field

$\omega$ is angular frequency

It is clear that the peak emf in an ac generator depends on :

The number of turns in the generator
Area of coils
Magnetic field

8 0

3 years ago