Answer:
Coefficient of dynamic friction= md= 0.09931
Explanation:
To determine the coefficient of dynamic friction we must first match the friction force that is permendicular to the normal force of the block and opposite to the drag force, to the component of the drag force in this same direction. This component on the X axis of the drag force will be:
F= 90N × cos(30°) = 77.9423N
This component on the X axis of the drag force must be equal to the dynamic friction force that is equal to the coefficient of dynamic friction by the normal force of the block weight:
F= md × m × g= 77.9423N
m= mass of the block
md= coefficient of dynamic friction
g= gravity acceleration
F= md × 80kg× 9.81 (m/s²)= 77.9423(kg×m/s²)
md= (77.9423(kg×m/s²) / 784.8 (kg×m/s²)) = 0.09931
Using the theorem of kinetic energy
1/2mVf² - 1/2mVi²= WF + Wp, Wp=0
WF = F. AB, AB=5m and F= 40N, m=20kg
so the final kinetic is KEf= 1/2mVf² = WF =<span>F. AB= 40*5=200J
</span>
the final velocity is 1/2mVf² <span>=200, implies Vf= sqrt(20)=2sqrt(5)m/s</span>
Answer:
Induced current, I = 0.5 A
Explanation:
It is given that,
number of turns, N = 20
Area of wire, 
Initial magnetic field, 
Final magnetic field, 
Time taken, t = 2 s
Resistance of the coil, R = 0.4 ohms
We know that due to change in magnetic field and emf will be induced in the coil. Its formula is given by :
Where
Let I is the induced current in the wire. It can be calculated using Ohm's law as :
I = 0.5 A
So, the magnitude of the induced current in the coil is 0.5 A. Hence, this is the required solution.
The sun is approximately 27,000 light years away from the center of our galaxy.
1. Take a breaker
2. Put a sieve on it
3. Pour the mixture and shake the sieve gently
4. Wait for the flour to fall. After the flour falls pour the rice from the sieve into other beaker then do experiment again for fair testing(optional)
