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3 years ago

If an atom has 3 protons, 3 electrons and 2 neutrons, what is the atom's electrical charge?

2 answers:

lina2011 [118]3 years ago

7 0

To know the charge of the atom given, we need to know the charges of the subatomic particles. Protons have positive charges, electrons have negative charges and lastly neutrons have no charges. So, you just have to add these charges up. Therefore, we have, 3 + -3 + 0 = 0, neutral charge for the atom.

babymother [125]3 years ago

5 0

The atoms electrical charge would be 0. As the electrical charge is calculated by taking the number of protons and subtracting it by the number of electrons. In this case the result is 0. (3-3).

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Find how many milliliters of NaOH should be used to reach the half-equivalence point during the titration of 20.00 mL 0.888 M bu

Varvara68 [4.7K]

Answer: The volume of NaOH solution required to reach the half-equivalence point is 0.09 mL

Explanation:

The chemical equation for the dissociation of butanoic acid follows:

$CH_3CH_2CH_2COOH\rightleftharpoons CH_3CH_2CH_2COO^-+H^+$

The expression of $K_a$ for above equation follows:

$K_a=\frac{[CH_3CH_2CH_2COO^-][H^+]}{[CH_3CH_2CH_2COOH]}$

We are given:

$[CH_3CH_2CH_2COOH]=0.888M\\K_a=1.54\times 10^{-5}$

$[CH_3CH_2CH_2COO^-]=[H^+]$

Putting values in above expression, we get:

$1.54\times 10^{-5}=\frac{[H^+]^2}{0.888}$

$[H^+]=-0.0037,0.0037$

Neglecting the negative value because concentration cannot be negative

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is butanoic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=\frac{0.0037}{2}M\text{ (half equivalence)}\\V_1=20.00mL\\n_2=1\\M_2=0.425M\\V_2=?mL$

Putting values in above equation, we get:

$1\times \frac{0.0037}{2}\times 20.00=1\times 0.425\times V_2\\\\V_2=\frac{1\times 0.0037\times 20}{1\times 0.425\times 2}=0.087mL$

Hence, the volume of NaOH solution required to reach the half-equivalence point is 0.09 mL

5 0

3 years ago

Determine what mass of carbon monoxide and what mass of hydrogen are required to form 6.0 kg of methanol by the reaction CO(g) +

siniylev [52]

Answer:

5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.

Explanation:

The balanced reaction:

CO (g) + 2 H₂ (g) -> CH₃OH (l)

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

CO: 1 mole
H₂: 2 moles
CH₃OH: 1 mole

Being the molar mass of each compound:

CO: 28 g/mole
H₂: 1 g/mole
CH₃OH: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CO: 1 mole* 28 g/mole= 28 grams
H₂: 2 moles* 1 g/mole= 2 grams
CH₃OH: 1 mole* 32 g/mole= 32 grams

Being 6 kg equivalent to 6000 grams (1 kg= 1000 grams), you can apply the following rules of three:

If by stoichiometry 32 grams of methanol are formed from 28 grams of carbon monoxide, 6000 grams of methanol are formed from how much mass of carbon monoxide?

$mass of carbon monoxide=\frac{6000 grams of methanol*28 grams of carbon monoxide}{32 grams of methanol}$

mass of carbon monoxide= 5250 grams= 5.25 kg

If by stoichiometry 32 grams of methanol are formed from 2 grams of hydrogen, 6000 grams of methanol are formed from how much mass of hydrogen?

$mass of hydrogen=\frac{6000 grams of methanol*2 grams of hydrogen}{32 grams of methanol}$

mass of hydrogen= 375 grams

5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.

8 0

3 years ago

What are the metals nonmetals and metalloids on periodic table?

deff fn [24]

Answer:

he line begins at boron (B) and extends down to polonium (Po). Elements to the left of the line are considered metals. Elements just to the right of the line exhibit properties of both metals and nonmetals and are termed metalloids or semimetals. Elements to the far right of the periodic table are nonmetals.

4 0

3 years ago

What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 193.9J of heat and the temperature rises 15.0

skad [1K]

Answer:

The specific heat capacity of silver is 0.24 j/g.°C.

Explanation:

Given data:

Mass of sample = 55.00 g

increase of temperature ΔT= 15.0 °C

Heat absorbed = 193.9 J

Specific heat capacity of silver = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance.

ΔT = change in temperature

Now we will put the values in formula.

193.9 J = 55.00 g × c ×15.0 °C

193.9 J = 825 g.°C × c

c = 193.9 J / 825 g.°C

c= 0.24 /g.°C

The specific heat capacity of silver is 0.24 j/g.°C.

5 0

3 years ago

What is the correct formula for the product represented by the letter x

ANTONII [103]

Then I would guess the answer is D because Na2OH is much more common and stable than Na2O is

3 0

4 years ago