$Concentration\ rate=\frac{mass\ of\ product}{mass\ of\ substance}*100\%\\\\
15\%=\frac{m_1}{ms_1}*100\%\\ms_1=10pints\\
15\%=\frac{m_1}{10}*100\%\\
\frac{15}{100}=\frac{m_1}{10}\ \ |*10\\
m_1=\frac{150}{100}=1,5pints\\\\
10\%=\frac{m_2}{15}*100\%\\
0,1=\frac{m_2}{15}\ \ |*15\\
1,5=m_2\\
Resulting\ solution:\\
ms=ms_1+ms_2=15+10=25pints\\m=m_1+m_2=1,5+1,5=3pints
\\\frac{m}{ms}*100\%=\frac{3}{25}*100\%=12\%$

7 0

2 years ago

Which planet’s surface is covered with red,iron-oxide dust?

Alenkasestr [34]

The answer is Mars, A

7 0

3 years ago

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For a particular reaction, ΔH° is 34.2 kJ and ΔS is 99.2 J/K. Assuming these values change very little with temperature, over wh

Nostrana [21]

Over 344.76 K the forward reaction will be spontaneous

calculation

ΔG = ΔH° -TΔs

if ΔG =0

therefore 0 =ΔH°-TΔs

ΔH° = TΔs

divide both side by Δs

T = ΔH°/Δs

convert 34.2 kj into j

that is 1 kj = 1000 j

34.2 kj =? j

by cross multiplication

=[34.2 kj x 1000j / 1 kj] = 34200 j

T is therefore = 34200 j÷99.2 j/k =344.76 k

if T is greater than 344.76 k the forward reaction will be spontaneous

3 0

3 years ago

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