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frozen [14]
3 years ago
7

What is an example of turning chemical energy into light energy?

Chemistry
1 answer:
levacccp [35]3 years ago
5 0
Chemical energy being changed into light energy would happen during phototsynthesis

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Acetic acid has a pKa of 4.74. Buffer A: 0.10 M HC2H3O2, 0.10 M NaC2H3O2 Buffer B: 0.30 M HC2H3O2, 0.30 M NaC2H3O2 Buffer C: 0.5
e-lub [12.9K]

Answer:

Buffer B has the highest buffer capacity.

Buffer C has the lowest buffer capacity.

Explanation:

An effective weak acid-conjugate base buffer should have pH equal to pK_{a} of the weak acid. For buffers with the same pH, higher the concentrations of the components in a buffer, higher will the buffer capacity.

Acetic acid is a weak acid and CH_{3}COO^{-} is the conjugate base So, all the given buffers are weak acid-conjugate base buffers. The pH of these buffers are expressed as (Henderson-Hasselbalch):

pH=pK_{a}(CH_{3}COOH)+log\frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}

pK_{a}(CH_{3}COOH)=4.74

Buffer A:    pH=4.74+log(\frac{0.10}{0.10})=4.74

Buffer B:   pH=4.74+log(\frac{0.30}{0.30})=4.74

Buffer C:   pH=4.74+log(\frac{0.10}{0.50})=4.04

So, both buffer A and buffer B has same pH value which is also equal to pK_{a} . Buffer B has higher concentrations of the components as compared to buffer A, Hence, buffer B has the highest buffer capacity.

The pH of buffer C is far away from pK_{a} . Therefore, buffer C has the lowest buffer capacity.

     

6 0
3 years ago
As a pendulum swings from its highest to its lowest position along an arc, what happens to its kinetic energy and potential ener
lara31 [8.8K]

C.

Explanation:

As a pendulum swings from its highest to its lowest position along an arc, what happens to its kinetic energy and potential energy? The potential energy decreases while the kinetic energy increases.

4 0
2 years ago
Help! I am in a hurry! Will get brainliest if correct!
sashaice [31]

Answer:

nonmetel

Explanation:

3 0
3 years ago
Read 2 more answers
What is meant by solvation?
Kamila [148]
Solvation describes the interaction of solvent with dissolved molecules.
6 0
3 years ago
A 100.0mL bubble of hot gases at 225 C and 1.80 atm escapes from an active volcano, what is the new volume of the bubble outside
Inessa05 [86]
<h3>Answer:</h3>

112.08 mL

<h3>Explanation:</h3>

From the question we are given;

  • Initial volume, V1 = 100.0 mL
  • Initial temperature, T1 = 225°C, but K = °C + 273.15

thus, T1 = 498.15 K

  • Initial pressure, P1 = 1.80 atm
  • Final temperature , T2 = -25°C

                                     = 248.15 K

  • Final pressure, P2 = 0.80 atm

We are required to calculate the new volume of the gases;

  • According to the combined gas law equation;

\frac{P1V1}{T1}=\frac{P2V2}{T2}

Rearranging the formula;

V2=\frac{P1V1T2}{T1P2}

Therefore;

V2=\frac{(1.80atm)(100mL)(248.15K)}{(498.15K)(0.80atm)}

V2=112.08mL

Therefore, the new volume of the gas is 112.08 mL

8 0
3 years ago
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