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Marizza181 [45]
3 years ago
15

A light bulb provides a resistance of 20 Ω to the 30 A current that runs through it. Determine the voltage of the battery in the

flashlight.
0.7 V
2 V
51 V
600 V
Physics
2 answers:
Kaylis [27]3 years ago
6 0

Answer:

The voltage of the battery in the flashlight is 600 v

Explanation:

<u><em>A light bulb provides a resistance of 20 Ω to the 30 A current that runs through it. Determine the voltage of the battery in the flashlight.</em></u>

<u><em /></u>

To determine the voltage of this battery,all we need to do is to use the formula;

V= IR

where v = voltage

I = current

R= resistance

From the question given;

resistance (I) is given to be 20   while current(I) is 30

We can now proceed to insert our values into the formula;

V= IR

V = 20 × 30

v = 600 v

The voltage of the battery in the flashlight is 600 v

likoan [24]3 years ago
4 0

Explanation:

Ohm's law:

V = IR

V = (30 A) (20 Ω)

V = 600 V

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C)T

Explanation:

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A 0.520-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of
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Explanation:

Given that,

Mass attached to spring

M = 0.52kg

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Amplitude A = 11.6 cm

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w = √15.385

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Generally,

The position of the object at equilibrium is

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Then, when x(t) = 9.6cm

9.6 = 11.6 Cos(3.92t)

Cos(3.922t) = 9.6/11.6

Cos(3.922t) = 0.8276

3.922t = ArcCos(0.8276)

Note: the angle is in radiant

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t = 0.152 second

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v(t) = -45.5Sin(3.922t)

Now, when t =0.152

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a(t) = -178.46 Cos(3.92×0.152)

a(t) = -178.46 Cos(0.596)

a(t) = -147.68 cm/s²

Magnitude of the acceleration is 147.68 cm/s²

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