<h2>F = kAρv²</h2>
Explained in the attachment !
<h3>Hope it helps you!!</h3>
Action-reaction forces : Select one:
1 answer:
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Explanation:
Given that,
Force,
Position of the particle,
(a) The toque on a particle about the origin is given by :
Taking the cross product of above two vectors, we get the value of torque as :
(b) Let is the angle between r and F. The angle between two vectors is given by :
Answer:
The magnitude of the magnetic force acting on the conductor is 0.75 Newton
Explanation:
The parameters given in the question are;
The length of the straight segment of wire, L = 25 cm = 0.25 m
The current carried in the wire, I = 5 A
The orientation of the wire with the magnetic field = Perpendicular
The strength of the magnetic field in which the wire is located, B = 0.60 T
The magnetic force, 'F', is given by the following formula;
F = ·L×
= I·L·B·sin(θ)
Where;
= The current flowing, I
L = The length of the wire
= The magnetic field strength, B
θ = The angle of inclination of the conductor to the magnetic field
Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;
F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N
Therefore
The magnitude of the magnetic force, F = 0.75 N.