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Ilya [14]
3 years ago
8

Two soccer players kick the same 1-kg ball at the same time in opposite directions. one kicks with a force of 20 n; the other ki

cks with a force of 12 n. what is the resulting acceleration of the ball, in m/s2.
Physics
2 answers:
REY [17]3 years ago
7 0

Answer:

8 m/s but just write 8

Explanation:

kolezko [41]3 years ago
6 0
We can solve the problem by using Newton's second law of motion:
\sum F = ma (1)
where
the term on the left is the resultant of the forces acting on an object
m is the mass of the object
a is the acceleration of the object

The mass of the ball in this problem is m=1 kg. Two forces are applied, in opposite directions, of 20 N and 12 N, therefore the resultant of the forces is
\sum F= 20 N-12 N=8 N

Therefore, we can rearrange eq.(1) and use these data to find the acceleration of the ball:
a= \frac{\sum F}{m}= \frac{8 N}{1 kg}=8 m/s^2
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Answer:

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Explanation:

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A long solenoid that has 1,130 turns uniformly distributed over a length of 0.430 m produces a magnetic field of magnitude 1.00
sweet-ann [11.9K]

Given Information:

Number of turns = N = 1130 turns

Length of solenoid = L = 0.430 m

Magnetic field = B =  1.0x10⁻⁴ T

Required Information:

Current = I = ?

Answer:

I = 0.0302 A

Explanation:

The current flowing in the solenoid winding can be found using

I = BL/μ₀N

Where μ₀ is the permeability of free space, N is the number of turns, B is the magnetic field and L is the length of solenoid

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or

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6 0
2 years ago
Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker poi
Nataly [62]

Answer

given,

mass of ball, m = 57.5 g = 0.0575 kg

velocity of ball northward,v = 26.7 m/s

mass of racket, M = 331 g = 0.331 Kg

velocity of the ball after collision,v' = 29.5 m/s

a) momentum of ball before collision

   P₁ = m v

   P₁ = 0.0575 x 26.7

   P₁ = 1.535 kg.m/s

b) momentum of ball after collision

   P₂ = m v'

   P₂ = 0.0575 x (-29.5)

   P₂ = -1.696 kg.m/s

c) change in momentum

    Δ P = P₂ - P₁

    Δ P = -1.696 -1.535

    Δ P = -3.231 kg.m/s

d) using conservation of momentum

  initial speed of racket = 0 m/s

  M u + m v = Mu' + m v

  M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)

  0.331 u' = 3.232

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change in velocity of the racket is equal to 9.76 m/s

5 0
3 years ago
A pulley lifts a 72-N load with a force of 24-N. The input distance is 2m and the output distance is 0.5m. What is the efficienc
Debora [2.8K]

Answer:

Explanation:

Work done on the lever ( input energy ) = force applied x input distance

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efficiency = output energy / input energy

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If a runner goes 500 meters with an average speed of 7.0 m/s. How long were they running?
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Explanation:

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