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LenaWriter [7]
3 years ago
15

You drop a small ball, and then a second small ball. When you drop the second ball, the distance between them is 3 cm. What stat

ement below is correct? Explain.
a) The distance between the ball stays the same
b) The distance between the balls decreases.
c) The distance between the balls increases.
Physics
1 answer:
Alja [10]3 years ago
3 0

Answer:

c) The distance between the balls increases.

Explanation:

If you drop the balls at the same time, regardless of their masses they accelerate equally, since they will be in free fall.

However, if you drop one of the balls earlier, then that ball will gain velocity, whereas the second ball has zero initial velocity. At the time the second ball is dropped, both balls have the same acceleration but different initial velocities.

According to the below kinematics equation:

x = v_0t + \frac{1}{2}at^2

The initial velocity of the first ball will make the difference, and the first ball will travel a greater distance than the second ball. Hence, their distance increases.

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Answer:

\omega_f = 585.37 \ rev/s

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)=  800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

I \omega_i = I' \omega_f

(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f

M\times 800 = ( M + m )\omega_f

3\times 800 = (3+1.1)\times \omega_f

2400 = (4.1)\times \omega_f

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Do changes that cannot be easily reserved such as burning observe the law of conversation of mass
Marina CMI [18]
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A transparent oil with index of refraction 1.28 spills on the surface of water (index of refraction 1.33), producing a maximum o
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Answer:

The thickness of the oil slick is 1.95\times10^{-7}\ m

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Given that,

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2\times1.28 \times t=1\times\times500\times10^{-9}

t = \dfrac{1\times\times500\times10^{-9}}{2\times1.28 }

t=1.95\times10^{-7}\ m

Hence, The thickness of the oil slick is 1.95\times10^{-7}\ m

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