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LenaWriter [7]
3 years ago
15

You drop a small ball, and then a second small ball. When you drop the second ball, the distance between them is 3 cm. What stat

ement below is correct? Explain.
a) The distance between the ball stays the same
b) The distance between the balls decreases.
c) The distance between the balls increases.
Physics
1 answer:
Alja [10]3 years ago
3 0

Answer:

c) The distance between the balls increases.

Explanation:

If you drop the balls at the same time, regardless of their masses they accelerate equally, since they will be in free fall.

However, if you drop one of the balls earlier, then that ball will gain velocity, whereas the second ball has zero initial velocity. At the time the second ball is dropped, both balls have the same acceleration but different initial velocities.

According to the below kinematics equation:

x = v_0t + \frac{1}{2}at^2

The initial velocity of the first ball will make the difference, and the first ball will travel a greater distance than the second ball. Hence, their distance increases.

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Awave has a period of 1. What is its frequency?
Andrei [34K]

Answer:

Frequency, f = 1 unit

Explanation:

It is given that,

Period of the wave, T = 1 unit

We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :

T=\dfrac{1}{f}

Or

f=\dfrac{1}{T}

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So, the frequency of the wave is 1 unit. Hence, this is the required solution.

4 0
3 years ago
A 10.0 kg ball weighs 98.0 N in air and weighs 65.0 N when submerged in water. The volume of the ball is:_________.A) 0.00245 m3
Kamila [148]

Answer: B) 0.00337 m3.

Explanation:

Given data:

Mass of the ball = 10kg

Weight of the ball in air = 98N

Weight of the ball in water = 65N

Solution:

To get the Volume of the ball when submerged in water, we divide the weight of the ball in water with the difference in apparent weight by 9.8m/s^2.

= 98 - 65 / 9.8

= 33 / 9.8

= 3.37kg

The volume of the ball is 3.37kg

The density of water is 1kg per Liter.

So 3.37 kg of water would have a volume of 3.37 Liters.

Therefore the ball would have a volume of 3.37 Liters (or 0.00337 cubic meters).

7 0
3 years ago
Question 2
Delvig [45]

Answer:

Approximately 73\; {\rm N}, assuming that the acceleration of this ball is constant during the descent.

Explanation:

Assume that the acceleration of this ball, a, is constant during the entire descent.

Let x denote the displacement of this ball and let t denote the duration of the descent. The SUVAT equation x = (1/2)\, a\, t^{2} would apply.

Rearrange this equation to find an expression for the acceleration, a, of this ball:

\begin{aligned} a &= \frac{2\, x}{t^{2}}\end{aligned}.

Note that x = 11\; {\rm m} and t = 1.5\; {\rm s} in this question. Thus:

\begin{aligned} a &= \frac{2\, x}{t^{2}} \\ &= \frac{2 \times 11\; {\rm m}}{(1.5\; {\rm s})^{2}} \\ &\approx 9.78\; {\rm m \cdot s^{-2}}\end{aligned}.

Let m denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is a, the net external force on this ball would be m\, a.

Since m = 7.5\; {\rm kg} and a \approx 9.78\; {\rm m\cdot s^{-2}}, the net external force on this ball would be:

\begin{aligned} (\text{net force}) &= m\, a \\ &\approx 7.5\; {\rm kg} \times 9.78\; {\rm m\cdot s^{-2}} \\ &\approx 73\; {\rm kg \cdot m \cdot s^{-2} \\ &= 73\; {\rm N} && (1\; {\rm N} = 1\; {\rm kg \cdot m\cdot s^{-2}}) \end{aligned}.

4 0
2 years ago
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