Answer:
Option a. Benzenecarbonitrile
Explanation:
You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.
As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.
This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.
phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.
Hope this helps
Tendons<span> may also attach muscles to structures such as the eyeball. A </span>tendon<span> serves to move the bone or structure. A </span>ligament<span> is a fibrous connective tissue which attaches bone to bone, and usually serves to hold structures together and keep them stable.</span>
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Answer:
Number of moles = 2 mol
Explanation:
Given data:
Mass of carbon = 24 g
Number of moles = ?
Solution:
Formula:
Number of moles = mass/ molar mass
Molar mass of carbon is 12 g/mol.
Now we will put the values in formula.
Number of moles = 24 g/ 12 g/mol
Number of moles = 2 mol
<u>Answer:</u> The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL
<u>Explanation:</u>
We are given:
32.0 % (v/v) alcohol solution
This means that 32 mL of isopropyl alcohol is present in 100 mL of solution
Volume of water = 100 - 32 = 68 mL
Volume of solution given = 795 mL
Applying unitary method:
In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL
So, in 795 mL of solution, the volume of isopropyl alcohol present will be = 
Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL
Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL