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charle [14.2K]
3 years ago
14

How much energy is required to heat a frozen can of juice (360 grams- mostly water) from 0 degrees Celsius ( the temperature of

an overcooled refrigerator) to 110 degrees ( the highest practical temperature within a microwave oven)?
Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

1,100,160J or 262.94 kcal

Explanation:

The juice is frozen at 0 degrees Celsius and I assume that it will become gas at 100 degrees Celsius. So we change the form of the water from solid to liquid, then to gas. That means we have to find out how much heat needed to change water form too, not only the heat needed to increase its temperature.

The latent heat of water is 4.2J/g °C while the heat of fusion is 334 J/g and the heat of vaporization is 2260 J/g. The energy needed will be:

360g * 4.2J/g °C * (110-0°C ) + 360g * 334 J/g + 360g * 2260 /g = 1,100,160J or 262.94 kcal.

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Hydrogen bonds are stronger than the dipole dipole attraction force present in any molecule.

<h3>What is bonding in molecules?</h3>

Bonding is a type of attraction force which is present between the different atoms or elements of any substance.

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Hence main difference is that hydrogen bond is only present between the hydrogen atom and more electronegative.

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2 years ago
Consider the reaction.
Alex_Xolod [135]

Note the signs of equilibrium:-

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if

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8 0
2 years ago
Water has a density of 1 g/cc. If you have 1 cc of water, how much mass does it contain?
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3 years ago
Consider a 1260-kg automobile clocked by law-enforcement radar at a speed of 85.5 km/h. If the position of the car is known to w
-BARSIC- [3]
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