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OverLord2011 [107]
3 years ago
9

Luminosity is the amount of energy emitted by a star each second. Stars radiate light over a broad range of frequencies in the e

lectromagnetic spectrum, from the low energy radio waves to high energy gamma rays. Energy emitted from stars is the result of
Chemistry
1 answer:
lapo4ka [179]3 years ago
7 0
Luminosity is the amount of energy emitted by a star each second. Stars radiate light over a broad range of frequencies in the electromagnetic spectrum, <span>from the low energy radio waves to high energy gamma rays. Energy emitted from stars is the result of fusion of gases within its core</span>
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Ksenya-84 [330]
Answer
B I’m pretty sure
Explanation
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3 years ago
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Who earned the nobel prize twice for their work with radioactivity
lord [1]

Answer:

Marie Curie, née Maria Salomea Skłodowska, (born November 7, 1867, Warsaw, Congress Kingdom of Poland, Russian Empire—died July 4, 1934, near Sallanches, France), Polish-born French physicist, famous for her work on radioactivity and twice a winner of the Nobel Prize.

Explanation:

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4 Al(s) + 3 O2(g) --&gt; 2Al2O3 (s) What mole ratio would you use to convert from the given quantity of moles of aluminum to the
ohaa [14]

Answer:

1:2

Explanation:

For every 4 moles of aluminum, there are 2 moles of aluminum oxide, so the mole ratio when converting from aluminum to alunmimum oxide is

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If you would like FREE tutoring in chemistry or another subject, check out www.growthinyouth.org.

5 0
3 years ago
A weather balloon is inflated to a volume of 27.3 L at a pressure of 738 mmHg and a temperature of 26.9 ∘C. The balloon rises in
sertanlavr [38]

Answer:

The new volume of the balloon is 46.1 L

Explanation:

Step 1: Data given

Initial volume of the balloon = 27.3 L

Initial pressure in the balloon = 738 mmHg = 0.97105 atm

Initial temperature in the balloon = 26.9 °C = 300.05 K

The pressure decreases to 375 mmHg = 0.493421 atm

The temperature lowers to -15.6 °C = 257.55 K

Step 2: Calculate the volume

P1*V1 / T1 = P2 *V2 / T2

⇒with P1 = the Initial pressure = 738 mmHg = 0.97105 atm

⇒with V1 = Initial volume of the balloon = 27.3 L

⇒with T1 = Initial temperature in the balloon = 26.9 °C = 300.05 K

⇒with P2 = the decreased pressure = 0.493421 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the lowered temperature = 257.55 K

0.97105 * 27.3 / 300.05 = 0.493421*V2 / 257.55

V2 = 46.1 L

The new volume of the balloon is 46.1 L

6 0
3 years ago
Which is produced by the dehydration of primary alcohols? A) an acid B) a ketone C) an ether D) an ester
Talja [164]
B.
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6 0
3 years ago
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