<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
- A certain circuit is composed of two series resistors
- The total resistance is 10 ohms
- One of the resistor is 4 ohms
<h3>
<u>To </u><u>Find </u><u>:</u><u>-</u></h3>
- We have to find the value of other resistor?
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
We know that,
In series combination,
- When a number of resistances are connected in series, the equivalent I.e resultant resistance is equal to the sum of the individual resistances and is greater than any individual resistance
<u>That </u><u>is</u><u>, </u>
Rn in series = R1 + R2 + R3.....So on
<u>Therefore</u><u>, </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
We have,
R1 + R2 = 10 Ω
4 + R2 = 10Ω
R2 = 10 - 4
R2 = 6Ω
Hence, The value of R2 resistor in series is 6Ω
Answer:
2.96 × 10^4 N
Explanation:
1 atm = 101325 N/m², pressure inside the airtight room = 1.02 atm, pressure outside due to hurricane = 0.91 atm
net pressure directed outward = P inside - P outside
net pressure = 1.02 - 0.91 = 0.11 atm
where 1 atm = 101325N/m²
0.11 atm = 0.11 × 101325 N/m² = 11145.75 N/m²
area of the square wall = l × l where l is the length of the wall in meters = 1.63 × 1.63 = 2.6569
net pressure = net force / area
make net force subject of the formula
net force = net pressure × area = 11145.75 × 2.6569 = 2.96 × 10 ^4 N
BBBBBBBB!!!!! ATOMIC MASSES :D
Answer:
241.8 N.
Explanation:
The force on branch provides a reaction to the ape's weight force plus the centripetal force needed to keep the gibbon in a circular motion of radius 0.60 m.
Centripetal force = mv^2/r
F = mg + mv²/r
F = m(g + v²/r)
where,
m = mass
= 9 kg
g = acceleration due to gravity
= 9.8 m/s²
v = 3.2 m/s
r = 0.60 m
F = 9 * (9.8 + 3.2²/0.60)
= 241.8 N.
Answer:
An engine with an electronic fuel injection system has high fuel pressure at idle because of high manifold vacuum. (option D)
Explanation:
Electronic fuel injection (EFI) system replaced carburetors back in the mid-1980s as the preferred method of supplying air and fuel to engines. The basic difference is that a carburetor uses intake vacuum and a pressure drop in the venturi, to siphon fuel from the carburetor fuel bowl into the engine. Whereas fuel injection system uses pressure to spray fuel directly into the engine.
However, under light load or at idle, a relatively high vacuum exists in the intake manifold. This means less fuel pressure is needed to spray a given volume of fuel through the injector. Under heavy load, engine vacuum drops to near zero.
Therefore, An engine with an electronic fuel injection system has high fuel pressure at idle because of high manifold vacuum.