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Nesterboy [21]
3 years ago
6

The attraction between earth and the moon is an example of ________ force. the attraction between earth and the moon is an examp

le of ________ force. electrical magnetic resultant tectonic gravitational
Physics
2 answers:
slega [8]3 years ago
6 0

Answer: Gravitational force.

Explanation:  The force that bounds the Earth and the moon is the gravitational force, and this is why the moon rotates around the Earth.

Now, here the moon is orbiting the Earth is a similar case of how the Earth orbits the Sun and such.

The moon has a given velocity perpendicular to the line that connects it with the Earth, and the gravitational force accelerates the moon in a perpendicular direction with respect to the velocity of the moon, and this is why the moon rotates and does not come towards the Earth.

Korolek [52]3 years ago
4 0

The answer is gravitational force. The gravitational force between the earth and the moon is the similar as between any other two masses in space.

Newton clarified that the force of attraction between two masses is the outcome of the weight of object one multiplied by the weight of objects two multiplied by the gravitational constant divided by the space between the two masses squared. 

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a basketball player can leap upward .65m how long does the basketball player remain in the air use 9.81m/s²​
tigry1 [53]

At the player's maximum height, their velocity is 0. Recall that

{v_f}^2-{v_i}^2=2a\Delta y

which tells us the player's initial velocity v_i is

0^2-{v_i}^2=-2g(0.65\,\mathrm m)\implies v_i=3.6\dfrac{\rm m}{\rm s}

The player's height at time t is given by

y=v_it-\dfrac g2t^2

so we find their airtime to be

0.65\,\mathrm m=\left(3.6\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2\implies t=0.36\,\mathrm s

6 0
3 years ago
How does the electrostatic force compare with the strong nuclear force in the
diamong [38]

Answer:

Strong nuclear force is 1-2 order of magnitude larger than the electrostatic force

Explanation:

There are mainly two forces acting between protons and neutrons in the nucleus:

- The electrostatic force, which is the force exerted between charged particles (therefore, it is exerted between protons only, since neutrons are not charged). The magnitude of the force is given by

F_E=\frac{kq_1 q_2}{r^2}

where k is the Coulomb's constant, q1 and q2 are the  charges of the two particles, r is the separation between the particles.

The force is attractive for two opposite charges and repulsive for two same charges: therefore, the electrostatic force between two protons is repulsive.

- The strong nuclear force, which is the force exerted between nucleons. At short distance (such as in the nucleus), it is attractive, therefore neutrons and protons attract each other and this contributes in keeping the whole nucleus together.

At the scale involved in the nucleus, the strong nuclear force (attractive) is 1-2 order of magnitude larger than the electrostatic force (repulsive), therefore the nucleus stays together and does not break apart.

3 0
3 years ago
Read 2 more answers
Which scenario will drain the battery in the circuit diagram fastest: three 20 W bulbs in positions one, two, and three or 80 W
kakasveta [241]

Answer:

See the explanation below.

Explanation:

If you connect the three bulbs 20 W each will have a total power of 60W.

Now we need to understand to assign the meaning of the word gap, that is, if the circuit is open at that point or if there is no bulb connected at that point.

If the circuit is open at Point 2, there will be no current in the circuit, so the battery will drain faster with the three bulbs 20W.

In the second event, where gap means that there are no bulbs connected at that point, it means that you have two bulbs connected in series of 80W each.

In this case the bulbs will consume 160W thus drain the battery faster than the three 20W bulbs connected in series.

3 0
3 years ago
The bulge of water on the side of earth closest to the moon produces _______.
Goryan [66]

That's a "high tide".

6 0
3 years ago
A new spacecraft is built with an engine that is able to produce constant acceleration of 1g, where g = gravity’s acceleration o
QveST [7]

given that acceleration due to gravity is g = 10 m/s^2

speed of the rocket will reach to 0.9c

v_f = 0.9* 3 * 10^8 = 2.7 * 10^8 m/s

now by kinematics

v_f = v_i + a*t

2.7 * 10^8 = 0 + 10*t

t = 2.7*10^7 s

Part b)

distance traveled by it in above time

d = v*t + \frac{1}{2}at^2

d = 0 + \frac{1}{2}*10*(2.7*10^7)^2

d = 3.645 * 10^{15} m

so this is the distance covered by the object

3 0
3 years ago
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