Options are as follow,
A. P₄O₁₀
B. PCl₅
C. Ca₃(PO₄)₂
<span>D. KH</span>₂PO₃
Answer;
The correct option is Option-D (KH₂PO₃).
Explanation:
Oxidation number of Phosphorous is calculated as,
As the normal oxidation number of K is +1, H is +1 and O is -2 so,
KH₂PO₃ = 0
0 shows that the molecule is neutral. Now puttion values of all elemnts except P,
(+1) + (+1)₂ + P + (-2)₃ = 0
+1 + 2 + P - 6 = 0
+3 + P - 6 = 0
+3 + P = +6
P = +6 - 3
P = +3
Answer D, because it's acid
There are 2.32 x 10^6 kg sulfuric acid in the rainfall.
Solution:
We can find the volume of the solution by the product of 1.00 in and 1800 miles2:
1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m
1.00 in * 1 m / 39.3701 in = 0.0254 m
Volume = 4.662 x 10^9 m^2 * 0.0254 m
= 1.184 x 10^8 m^3 * 1000 L / 1 m3
= 1.184 x 10^11 Liters
We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70:
[H+] = 10^-pH = 10^-3.7 = 0.000200 M
[H2SO4] = 0.000100 M
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid:
1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4
We can now calculate for the mass of sulfuric acid in the rainfall:
mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
= 2.32 x 10^9 g * 1 kg / 1000 g
= 2.32 x 10^6 kg H2SO4
