1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arte-miy333 [17]
2 years ago
10

motorcycle starting from rest cover 200 metre distance in 6 second calculate final velocity and acceleration of the motorcycle ​

Physics
1 answer:
mash [69]2 years ago
6 0
<h2>Answer:</h2><h2>V=200m</h2><h2><em><u>time=6s</u></em></h2><h2><em><u>time=6s initial velocity=0</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+a</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value,</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 200/3/6=a </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 200/3/6=a 200/18-a </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 200/3/6=a 200/18-a a 100/9m/s^2</u></em></h2>

You might be interested in
Help!?!? Please and thank you
natita [175]
C is probably the correct one
3 0
3 years ago
Read 2 more answers
Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 65.3 ◦ . The velo
yanalaym [24]

Answer:

Plane will 741.6959 m apart after 1.7 hour                    

Explanation:

We have given time = 1.7 hr

So if we draw the vectors of a 2d graph we see that the difference in angles is   = 102^{\circ}-65.3^{\circ}=36.7^{\circ}

Speed of first plane  = 730 m/h

So distance traveled by first plane = 730×1.7 = 1241 m

Speed of second plane = 590 m/hr

So distance traveled by second plane = 590×1.7 = 1003 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.

Using the law of cosine, r^2 representing the distance between the planes, we see that:

r^2=1241^2+1003^2-2\times 1003\times 1241cos(36.7)=550112.8295

r = 741.6959 m

3 0
3 years ago
Observe the given figure and find the the gravitational force between m1 and m2.​
Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

8 0
2 years ago
Two positive charges of 6 µC are separated by a distance of 50 cm in air. What is the electric field strength at the midpoint of
attashe74 [19]

Answer:

The electric field strength at the midpoint of the line joining the charges is zero (0)

Explanation:

Given that the two charges are both positive (same charge) and are equal in magnitude that is 6uC. The electric field strength at the midpoint of the line joining the two charges will be equal and opposite in magnitude, therefore they will cancel each other out and the electric field strength at this point will be equal to zero.

4 0
3 years ago
A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

7 0
3 years ago
Other questions:
  • if an average cloud has a density of 0.5 g/m3 and has a volume of 1,000,000,000 m3,what is the weight of an average cloud
    10·1 answer
  • Block A, with a mass of 6.0 kg, is sliding across a frictionless track at 65 m/s when it collides with Block B ( 9.0 kg) which i
    7·1 answer
  • If the back of the truck is 1.3 m above the ground and the ramp is inclined at 22 ∘ , how much time do the workers have to get t
    12·1 answer
  • Which of the following elements are non-reactive because their outer electron energy levels are full?
    9·1 answer
  • Why do we feel cool when we spray perfume in our body​
    5·2 answers
  • Find the frequency of a wave produced by a generator that emits 100 pulses in 2.0 s.
    5·1 answer
  • Name any two liquid which are found in our human eyes​
    14·1 answer
  • los murcielagos se orientan en la oscuridad emitiendo ondas de ultrasonido que,al relajarse con los objetos, le proveen informac
    6·1 answer
  • The acceleration due to gravity on Earth is 9.81 m/s² [down]. A hockey puck was launched from the ice with a velocity of 26.9 m/
    15·1 answer
  • Can someone answer this please I’ll give brainliest
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!