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Arte-miy333 [17]
2 years ago
10

motorcycle starting from rest cover 200 metre distance in 6 second calculate final velocity and acceleration of the motorcycle ​

Physics
1 answer:
mash [69]2 years ago
6 0
<h2>Answer:</h2><h2>V=200m</h2><h2><em><u>time=6s</u></em></h2><h2><em><u>time=6s initial velocity=0</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+a</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value,</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6</u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 200/3/6=a </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 200/3/6=a 200/18-a </u></em></h2><h2><em><u>time=6s initial velocity=0 final velocity=200/6=100/3m/s v=u+aputting value, 200/3=0+ax6 200/3-ax6 200/3/6=a 200/18-a a 100/9m/s^2</u></em></h2>

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