Ask question

Ask question

All categories

3 years ago

8

imagine the first Olympic Games conducted on the moon in a specially designed dome. state and explain which sports would produce

new records and which would not

1 answer:

Anastaziya [24]3 years ago

4 0

Rhythmic gymnastics, trampoline gymnastics, javelin, diving, volleyball, and more due to the lack of gravity on the moon.

You might be interested in

Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as sh

puteri [66]

Answer:

F = 19.1 N

Explanation:

To find the force exerted by the string on the block you use the following formula:

$F=kx$ (1)

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

$F=(95.5N/m)(0.200m)=19.1N$

Hence, the force exterted on the block is 19.1 N

8 0

3 years ago

how much force is needed to move a brick with a mass of 345-kg a distance of 28m while doing 1008 j of work?

Travka [436]

    Work = (force) x (distance)

   1,008 J = (force) x (28 m)

Divide each side by 28m : (1,008 kg-m²/sec²) / (28 m) = force

   Force = 36 kg-m/s² = 36 Newtons .
      (about 8.1 pounds)

It doesn't matter what that force accomplishes.
It could be moving a brick, lifting a fish, or pushing a little red wagon.
In order to do 1,008 joules of work in 28 meters, it takes 36 N of force,
in the direction of the 28 meters.

5 0

3 years ago

Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×10^7 light-years from Earth. If the lifetime of a human

kupik [55]

Answer:

0.9999986*c

Explanation:

The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

$\Delta t = \Delta t' * \sqrt{1 - (\frac{v}{c})^2}$

Where

Δt is the travel time as seen by a passenger

Δt' is the travel time as seen by someone on Earth

v is the speed of the ship

c is the speed of light in vacuum

We can replace the fraction v/c with x

$\Delta t = \Delta t' * \sqrt{1 - x^2}$

$\sqrt{1 - x^2} = \frac{\Delta t}{\Delta t'}$

$1 - x^2 = (\frac{\Delta t}{\Delta t'})^2$

$x^2 = 1 - (\frac{\Delta t}{\Delta t'})^2$

$x = \sqrt{1 - (\frac{\Delta t}{\Delta t'})^2}$

$x = \sqrt{1 - (\frac{70}{2.54*10^7})^2} = 0.9999986$

It would need to travel at 0.9999986*c

5 0

3 years ago

Land plants are adapted to survive on land through stomata to regulate water regulation, specialized cells, structures that coll

Law Incorporation [45]

Answer:

stomata to regulate water

specialized cells

Explanation:

Land plants are able to successfully adapt to staying on land through the use of stomata to regulate water loss and through the development of specialized cells that give support to grow erect.

Water regulation is important for the survival of plants on land, otherwise, they may face desiccation as a result of the heat from the sun. <u>The stomata is a structure found on the leaves of land plants that open and close to regulate the amount of water lost to the environment through evapotranspiration.</u> When there is adequate water and the plant can afford to lose some water, the stomata open, otherwise, the stomata close.

Support is also important for land plant's survival and the development of specialized cells in the form of <em>sclerenchyma cells</em> take care of this. The <em>fib</em>ers and <em>sclerids</em> are two types of sclerenchyma cells that primarily function to support the land plants.

8 0

3 years ago

In the graph, during which time period does the particle undergo the greatest displacement?

VMariaS [17]

I'm not very good with Physics but of what I do know I'd go with point B / 4seconds

I apologize in advance if that is incorrect.

5 0

3 years ago