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3 years ago

A box contains ten cards labeled Q, R, S, T, U, V, W, X, Y, and Z. One card will be randomly chosen.

Mathematics

1 answer:

Triss [41]3 years ago

8 0

Answer: 2/5

Step-by-step explanation: The total number of letters available to choose from is 10. You want to know the probability of 4 of those 10. So you divide 4/10. When you simplify that fraction it becomes 2/5.

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For a craft each student will need five rubber bands.There.There are eight students.Rubber bands come in bags of nine. How many

matrenka [14]

Answer:

40 rubber bands are needed

5 rubber bands will be left from 5 bags of of rubber band

Step-by-step explanation:

Each student will need five rubber bands.

There are eight students

Total rubber bands needed = rubber bands per student × number of students

= 5 × 8

= 40

Total rubber bands needed = 40

Rubber bands come in bags of nine.

Number of bags needed = Total rubber bands needed / number of rubber bands in each bag

= 40 / 9

= 4.44 bags

It is impossible to get decimal number of rubber bands bag, so, the next whole number after 4 is 5

5 rubber bands bags will be bought which = 5 × 9

= 45 rubber bands

Only 40 rubber bands are needed

Left over rubber bands = 45 - 40

= 5 rubber bands

5 0

2 years ago

45^2 ÷ 78 = ????????

elena55 [62]

$\frac{(45)^2}{78}$

To solve the problem find the value of (45)^2 at first

$(45)^2=2025$ $\frac{2025}{78}=25\text{ R75}$

The answer is 25 with the remainder 75

$25\frac{75}{78}$

You can simplify the fraction to be 25/26

$25\frac{25}{26}$

3 0

1 year ago

Solve for x. 2=4x-6

77julia77 [94]

Answer:

x = 2

Step-by-step explanation:

Rewrite the equation as 4x - 6 = 2

Move all terms not containing x to the right side of the equation:

Add 6 to both sides of the equation.

4x = 2 + 6

Add 2 and 6.

4x = 8

Divide each term by 4 and simplify.

Divide each term in 4x = 8 by 4.

$\frac{4x}{4} =\frac{8}{4}$

Reduce the expression by cancelling the common factors.

$x=\frac{8}{4}$

Divide 8 by 4.

x = 2

8 0

2 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago

The actual answer is 144. I have the proof right here:

Soloha48 [4]

Answer:

do you need help with anything.?

Step-by-step explanation:

6 0

2 years ago