Answer:
12,608 kPa
Explanation:
First we need to convert the density to standard units, that is kg/m^3
0.85 g/cm^3 = 0.85 × 
= 0.85 × 1000 = 850 kg/m^3
Pressure of oil = pressure at surface + rho × g × h
= 101,000 + (850×9.81×1500)
= 12,608 kPa
The units in the part 'rho.g.h' will cancel out against each other and you will be left with the unit Pascals - which is the unit for pressure.
Hope that answers the question, have a great day!
Answer:
(a) Current flowing through truck battery is 180 A
(b) Time taken in calculator is 333.33 s
Explanation:
(a) Given:
The charge on the truck battery,q = 720 C
Time, t = 4.00 s
Consider I be the current flowing through truck battery.
The relation between current, charge and time is:
I = q/t
Substitute the suitable values in the above equation.
I = 180 A
(b) Given:
The charge on the calculator,q = 7.00 C
The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A
Consider t be the time.
The relation between current, charge and time is:
t = q/I
Substitute the suitable values in the above equation.
I = 333.33 s
This would be B, 5cm/sec.
To get this answer you would need to divided 25 which is how large the ramp is, and 5 seconds, the amount of time it took to travel down the ramp.
Answer:
735 J
Explanation:
Total height reached(displaced)=10x15 cm
= 10 x 15/100 m
= 1.5 m
Workdone = F.S (force x displacement)
Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m
Hence,
Workdone = 50 x 9.8 x 1.5 J
= 735 J
Answer:
91.5 m/s
Explanation:
m = mass of clay = 12 g = 0.012 kg
M = mass of wooden block = 100 g = 0.1 kg
d = distance traveled by the combination before coming to rest = 7.5 m
μ = Coefficient of friction = 0.65
V = speed of the combination of clay and lock just after collision
V' = final speed of the combination after coming to rest = 0 m/s
acceleration caused due to friction is given as
a = - μ g
a = - (0.65) (9.8)
a = - 6.37 m/s²
Using the kinematics equation
V'² = V² + 2 a d
0² = V² + 2(- 6.37) (7.5)
V = 9.8 m/s²
v = speed of clay just before collision
Using conservation of momentum
m v = (m + M) V
(0.012) v = (0.012 + 0.100) (9.8)
v = 91.5 m/s
