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rusak2 [61]
3 years ago
14

These type of winds are located between 30 and 60 degrees latitude on the globe.

Physics
1 answer:
vaieri [72.5K]3 years ago
7 0

<u>B</u> option is correct    .

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A 3900 kg truck is moving at 6.0 m/s what is the kinetic energy
Stolb23 [73]

Answer:

70200J

Explanation:

k.E = 1/2mv^2

K.E = 1/2(3900)(6)^2

3 0
2 years ago
Read 2 more answers
A cyclist overcomes a resistive force of 30 N in order to cycle 30 m. It takes her 6 seconds to cycle this distance. Calculate t
zmey [24]

Answer:

Power = 15[W]

Explanation:

This problem can be solved using the work definition.

Work is equal to the product of the force by the distance, for this problem we have:

F = force = 30 [N]

d = distance = 30 [m]

w = work = F * d = 30*30 = 900 [J], "units in joules"

The power is defined as the work done in an interval of time.

P = w / t

where:

t = time [s]

therefore

P = w / t

P = 900 / 6

P = 150 [W] "units in watts"

6 0
2 years ago
Help me please
agasfer [191]

Answer:

For a velocity versus time graph how do you know what the velocity is at a certain  time?

Ans: By drawing a line parallel to the y axis (Velocity axis) and perpendicular to the co-ordinate of the Time on the x axis (Time Axis). The point on the slope of the graph where this line intersects, will be the desired velocity at the certain time.

_____________________________________________________

How do you know the acceleration at a certain time?

Ans: We\ know\ that\ acceleration = \frac{Final\ velocity-Initial\ Velocity}{Time\ taken}

Hence,

By dividing the difference of the Final and Initial Velocity by the Time Taken, we could find the acceleration.

_________________________________________________________

How do you know the  Displacement at a certain time?

Ans: As Displacement equals to the area enclosed by the slope of the Velocity-Time Graph, By finding the area under the slope till the perpendicular at the desired time, we find the Displacement.

_________________________________________________________

4 0
2 years ago
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
White raven [17]

Answer:

400ft.    32ft/s       -32ft/s

Explanation:

In reality the gravitational acceleration is 9.81 so the quadratic coefficient of the function should be 9.81/2

Anyway for the sake of assumtion let us takes=160t-16t^2

 

ds/dt=160-32t=0

 

t=160/32= 5 seconds.

s=160*160/32-16*(160/32)^2= 400 mts

 

 

s=384 mts

160t-16t^2=384

i.e

16t^2-160t+384=0

 

t^2-10t+24=0

(t-6)(t-4)=0

t=[4,6]

we have to take t=4 because it is all the up i.e <5

 

velocity =v=ds/dt=160-32t

 

v=160-32*4=32 ft/sec still going up

 

for all the way down take t=6 whuch is >5

 

v=160-6*32=-32 ft/sec (falling down!!!)

6 0
2 years ago
Select the correct answer.
Vesna [10]

Answer:

C

Explanation:

Radiant= list onto solar panels, Electric= solar into power, Radiant= Electric into light

8 0
2 years ago
Read 2 more answers
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