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3 years ago

what is the molarity of a solution prepared by dissolving 20.0 g of NaOH in enough water to make 0.50 L og solution?

Chemistry

1 answer:

Alona [7]3 years ago

6 0

Answer:

Molarity of a solution = 1 mol / L

Explanation:

Given:

Amount of NaOH =20 g

Amount of water = 0.50 l

Find:

Molarity of a solution

Computation:

1 mol of NaOH = 40 g

So,

Moles of NaOH = 20 / 40 g = 0.50 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.50 / 0.50

Molarity of a solution = 1 mol / L

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Molarity has been defined as the moles of substance in a liter of solution. Molarity has been expressed as:

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Answer :

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

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Explanation :

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The equilibrium expression of $HC_2H_3O_2$ will be:

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

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The equilibrium expression of $Co(H_2O)_6^{3+}$ will be:

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The equilibrium expression of $CH_3NH_3^+$ will be:

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

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3 years ago