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jolli1 [7]
3 years ago
8

Electron movement in the bonding of Group ___ elements with Group 7A elements is best described as ______________

Physics
2 answers:
spin [16.1K]3 years ago
8 0

Answer:

<h2>Group 1A</h2><h2>Ionic bond or electrostatic bond</h2>

Explanation:

  • Bond is a type of energy that is responsible to hold two or more same or different types of atoms.
  • On the basis of bond formation, the bond may be an ionic bond, covalent bond, coordinate bond and some other.  
  • Group 7A elements like chlorine, bromine and some other has 7 electrons in its outermost shell so it receives 1 electron to complete its octet and thus the formation of chloride or other ions takes place having a negative charge.
  • So 1A group like sodium and some other has 1 electron in its outermost shell and thus loses 1 electron to obtain octane and thus form a positive ion.  
  • Thus attraction takes place between positive ions like sodium ions and negative ions like chloride ions and a bond is formed that is known as an ionic bond or electrostatic bond.
lesya692 [45]3 years ago
3 0

Answer:

2A; valence electrons moving from the metal to the nonmetal to create a crystalline solid.

Explanation:

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A particle of unit mass moves in a potential V(x)= ax^2+b/x^2 . Where a and b are constnts. Calcuate the angular frequency of sm
Sholpan [36]

Answer:

Explanation:

Given

Potential Energy is given by

U(x)=ax^2+\frac{b}{x^2}

And Force is given by

F=-\frac{\mathrm{d} U}{\mathrm{d} x}

Particle will be at equilibrium when Potential Energy is either minimum or maximum

F=-\left ( 2ax-\frac{2b}{x^3}\right )

i.e.ax=\frac{b}{x^3}

x_0=(\frac{b}{a})^{0.25}

So angular Frequency of small oscillation is given by

\omega =\sqrt{\frac{U''(x)}{m}}

for m=1

we get    \omega =\sqrt{\frac{U''(x_0)}{1}}

U''(x_0)=2a+6a= 8a

\omega =\sqrt{8a}

4 0
3 years ago
A wave has a wavelength of 4. 9 m and a velocity of 9. 8 m/s. The medium through which this wave is traveling is then heated so
tatiyna

The wavelength of a wave is obtained by taking the ratio of wave speed and frequency.

The wavelength of the heated wave is 9.8 m. Hence, option (b) is correct.

What is frequency of a wave?

The number of oscillations completed by a wave in one second is known as the frequency of a wave. It is expressed as the ratio of the velocity of the wave to its wavelength.

Given data-

The wavelength of the wave is, \lambda = 4.9 \;\rm m.

The velocity of the wave is, v = 9.8 m/s.

The mathematical expression for the frequency of the wave is,

f = \dfrac{v}{\lambda}

Solving as,

f = \dfrac{9.9}{4.9}\\\\f =2 \;\rm Hz

Now, with constant frequency and the double magnitude of velocity (v' = 2 × 9.8 = 19.6 m/s). The wavelength of the heated wave is calculated as,

f = \dfrac{v'}{\lambda'}

here,

\lambda' is the wavelength of the heated wave.

Solving as,

2 = \dfrac{19.6}{\lambda'}\\\\\lambda' = \dfrac{19.6}{2}\\\\\lambda' = 9.8 \;\rm m

Thus, we can conclude that the wavelength of the heated wave is 9.8 m. Hence, option (b) is correct.

Learn more about the frequency of wave here:

brainly.com/question/1324797

3 0
3 years ago
A sharp edged orifice with a 50 mm diameter opening in the vertical side of a large tank discharges under a head of 5m. If the c
Sever21 [200]

Answer:

0.24

Explanation:

See attached file

3 0
3 years ago
A truck traveled 400 meters north in 80 seconds and then it traveled 300 meters east in 70 seconds. The magnitude of the average
Varvara68 [4.7K]

Answer:

3.3m/s

Explanation:

You first get the total time (80 + 70 = 150s).

Then you would find the displacement of the truck. To do that you would do component method (vector addition), so since its a right triangle (North and East), displacement is 400^2 + 300^2 = d^2.

d= 500m.

So now that you have displacement and time, you can find the velocity:

v=d/t

v=500/150

v=3.3

5 0
3 years ago
Four complete waves pass the duck in one second the frequency of this wave is
galben [10]
The frequency of a wave is the number of complete oscillations passing a given point per second.

In this case, assuming the duck is stationary, we have 4 complete waves passing the duck in one second: therefore, the frequency of the wave is
f= \frac{4}{1 s}=4 Hz
3 0
3 years ago
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