All categories

3 years ago

A doctor has a patient blow on one side of a U-shaped tube that is partially

Physics

1 answer:

mart [117]3 years ago

8 0

Answer:

A. 150 Pa

Explanation:

Answer is 150 Pa

You might be interested in

How much time does it take a person to walk 12 km north at a velocity of 6.5 km/hr

Stella [2.4K]

1.8461 km/hr Well i need more characters so i might as well type a beautiful sentence for you to read and waste your time on.

3 0

3 years ago

. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. T

Serggg [28]

Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

I = F t = Δp

in this case the final velocity is zero

F t = 0 -m v₀

F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

F₁ = -p₀ / 0.1

F₁ = - 10 p₀

barrier collapses

F₂ = -p₀ / 1

let's look for the relationship of the forces

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

5 0

3 years ago

this refers to the process of manufacturing that introduced powered machinery to the production of goods

Sidana [21]

This had to do with gain power and trade inequality business

5 0

3 years ago

A single frictionless roller-coaster car of mass m = 750. kg tops the first hill with speed v = 15.0 m/s at height h = 20.0 m as

Law Incorporation [45]

i will give you 25 points sorry becuase i can't help with that

3 0

3 years ago

Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the

IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency $f= 6.37\times10^{14}\ Hz$

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{c}{f}$

where, c = speed of light

f = frequency

Put the value into the formula

$\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}$

$\lambda=471\ nm$

We need to calculate the distance between the two slits

$m\times \lambda=d\sin\theta$

$d =\dfrac{m\times\lambda}{\sin\theta}$

Where, m = number of fringe

d = distance between the two slits

Here, $\sin\theta =\dfrac{y}{l}$

Put the value into the formula

$d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}$

$d=40.11\times10^{-6}\ m$

$d = 40.11\ \mu m$

Hence, The distance between the two slits is 40.11 μm.

7 0

3 years ago