Answer:
The vertical distance that the ski jumper fell is 417.45 m.
Explanation:
Given;
initial horizontal velocity of the jumper,
= 26 m/s
horizontal distance of the jumper, dx = 240 m
The time of the motion is given by;
dx = Vₓt
t = dx / Vₓ
t = 240 / 26
t = 9.23 s
The vertical distance traveled by the diver is given by;
![d_y = V_yt + \frac{1}{2}gt^2](https://tex.z-dn.net/?f=d_y%20%3D%20V_yt%20%2B%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
initial vertical velocity,
, = 0
![d_y = \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m](https://tex.z-dn.net/?f=d_y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2%5C%5C%5C%5Cd_y%20%3D%20%5Cfrac%7B1%7D%7B2%7D%289.8%29%289.23%29%5E2%5C%5C%5C%5Cd_y%20%3D%20417.45%20%5C%20m)
Therefore, the vertical distance that the ski jumper fell is 417.45 m.
The acceleration of this car is equal to 5
.
<u>Given the following data:</u>
- Initial velocity = 0 m/s (assuming it's starting from rest).
To determine the acceleration of this car:
<h3>How to calculate acceleration.</h3>
In Science, the acceleration of an object is calculated by subtracting the initial velocity from its final velocity and dividing by the time.
Mathematically, acceleration is given by this formula:
![a = \frac{V\;-\;U}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7BV%5C%3B-%5C%3BU%7D%7Bt%7D)
<u>Where:</u>
- U is the initial velocity.
- is the time measured in seconds.
Substituting the given parameters into the formula, we have;
![a = \frac{10\;-\;0}{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B10%5C%3B-%5C%3B0%7D%7B2%7D)
Acceleration, a = 5 ![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
Read more on acceleration here: brainly.com/question/24728358
Answer:
Species distribution
Explanation:
Species dispersion patterns—or distribution patterns—refer to how the individuals in a population are distributed in space at a given time. The individual organisms that make up a population can be more or less equally spaced.
Answer:
Explanation:
E=(σ/ε0)
As noted by Dirac the field is the same no matter how far you are from the sheet. When your charge covers a conducting plane, as in your case, the field is, D/eo ,(D is charge density). Because the field inside the conductor (no matter how thin) is zero. The only time the field is, D/2eo, is when you have just a sheet of charge, by itself, not on a conducting plane."
The answer is "A" Endothermic. Hope that helped :)