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Dima020 [189]
3 years ago
11

If an insulated (power side) wire rubbed through a part of the insulation and the wire conductor touched the steel body of a veh

icle, the type of failure would be called a(an)
Physics
1 answer:
ohaa [14]3 years ago
4 0

Answer:

a short-to-ground

Explanation:

Many failures that occur in vehicles can be diagnosed as electrical problems. The reason for these usually relate mainly to the electricity generated in the battery or alternator, in the ignition system as well as those produced by blown wires or fuses.

Cables or fuses: a blown fuse or a damaged electrical wire or one that is making ground or earth effect can be the cause of an electrical problem. Keep in mind that everyone is connected to each other through the wires of the electrical system. Fuses protect car components from power surges. If you have a problem with one, check it to see if you will have to replace it.

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To construct an oscillating LC system, you can choose from a 11 mH inductor, a 6.0 μF capacitor, and a 4.2 μF capacitor. What ar
Free_Kalibri [48]

Answer:

a. 475.14 Hz

b. 1959 Hz

c. 2341.53 Hz , 3053.34 Hz

Explanation:

f = \frac{1}{2\pi*\sqrt{C*L}}

a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF  replacing:

f = \frac{1}{2\pi*\sqrt{C*L}}f=\frac{1}{2\pi*\sqrt{10.2uF*11mH}}

f = 475.14 Hz

b. second smallest use the capacitive 6 uF so:

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{6uF*11mH}}

f = 1959Hz

c. second largest and largest oscillation first combination so:

Use 4.2 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{4.2uF*11mH}}

f = 2341.53 Hz

And finally largest oscillation cap in serie so:

C=\frac{c_1*c_2}{c_1+c_2}=\frac{4.2uF*6.0uf}{4.2uf+6.0uF}

C=2.47 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{2.47uF*11mH}}

f =  3053.34 Hz

5 0
3 years ago
How does conserving and recycling paper help manage energy resources?
hammer [34]
B is true, however that is not a way in which conserving and recycling paper helps manage energy sources...
8 0
3 years ago
Please help me find b) and d):
maks197457 [2]

Answer:

wow it's so hard

8 0
3 years ago
Please reply to me.
inysia [295]
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ It would be C

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

6 0
4 years ago
Read 2 more answers
Malcolm and Ravi raced each other. The average of their maximum speeds was 260 km/h If doubled, Malcolm's maximum speed would be
AfilCa [17]

Answer

Given,

Average speed of Malcolm and Ravi = 260 km/h

Let speed of the Malcolm be X and speed of the Ravi Y.

From the given statement

\dfrac{X+Y}{2}=260

X + Y = 520 ....(i)

2X - Y = 80  ....(ii)

Adding both the equations

3 X = 600

 X = 200 km/h

Putting value in equation (i)

Y = 520 - 200

Y = 320 Km/h

Speed of Malcolm = 200 Km/h

Speed of Ravi = 320 Km/h

8 0
3 years ago
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