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noname [10]
4 years ago
6

Mount Tambora, in Indonesia, erupted in April 1815, spewing huge amounts of fine ash into the air. The ash quickly spread throug

hout the upper atmosphere, reducing the amount of sunlight in the area. This led to a famine that killed at least 80,000 people. How did the eruption of Mount Tambora cause a famine?
Physics
1 answer:
fredd [130]4 years ago
6 0
Crops need sunlight to grow as well as water.

Reduced sunlight means reduced growth rate of crops means reduced crop yield means reduced number of mouths each yield can feed means famine means death.
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How is the pressure of a gas related to its concentration of particles?
solniwko [45]
As the volume of gas decreases, the pressure concentration of particles will increase.
7 0
3 years ago
A stationary siren emits sound of frequency 1000 Hz and wavelength 0.343 m. An observer who is moving toward the siren will meas
Ainat [17]

Answer:

f>1000Hz and wavelength=0.343 m

Explanation:

We are given that

Frequency of stationary siren,f=1000 Hz

Wavelength of stationary sound,\lambda=0.343 m

When a observer is moving towards the siren then the frequency increases.

Therefore,an observer who is moving towards the siren measure a frequency >1000 Hz.

The wavelength depends upon the speed of source.

But we are given that siren is stationary.

Therefore, source is not moving and then the wavelength remains same.

f>1000Hz and wavelength=0.343 m

4 0
3 years ago
A car accelerates uniformly from rest to a speed of 22.4 km/h in 6.1 s. find the distance it travels during this time.
stepladder [879]
You will need to add 22.4+6.1
7 0
3 years ago
A 2 kg body is dropped from a height of 3 m. Calculate:
NikAS [45]

Answer:

   a) 6.26 m/s

   b) 7.67 m/s

Explanation:

The potential energy at height h0 is initially ...

  PE0 = mgh0

At height h1, the potential energy is ...

  PE1 = mgh1

The difference in potential energy is converted to kinetic energy:

  PE0 -PE1 = KE1 = (1/2)m(v1)^2

Solving for v1, we have ...

  mg(h0 -h1) = (1/2)m(v1)^2

  2g(h0 -h1) = (v1)^2

  v1 = √(2g(h0 -h1))

__

a) When the body is 1 m high, its speed is ...

  v = √(2(9.8)(3 -1)) ≈ 6.26 m/s . . . at 1 m high

__

b) When the body is 0 m high, its speed is ...

  v = √(2(9.8)(3 -0)) ≈ 7.67 m/s . . . when it reaches the ground

3 0
3 years ago
Find the magnitude of the vector v given its initial and terminal points. Round your answer to four decimal places.
Sliva [168]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is |v| = 6.93

Explanation:

From the question we are told that

    The initial point is (x_1 , y_1 , z_1 ) = (-1 , 7 , 4 )

    The  terminal point is  (x_2 , y_2 , z_2) = (-5 , 11, 8 )

Generally the magnitude of the vector is mathematically represented as

     |v| = \sqrt{(x_2 -x_1 )^2 + (y_2 - y_1 )^2 + (z_2 -z_1)^2}

=>   |v| = \sqrt{(-5 -(-1) )^2 + (11 - 7 )^2 + (8 -4)^2}

=>   |v| = 6.93

3 0
3 years ago
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