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Natali5045456 [20]
4 years ago
7

According to Newton's law of universal gravitation, which of these objects would have the strongest gravitational force?

Physics
2 answers:
trasher [3.6K]4 years ago
8 0
It is the queen size bed
sattari [20]4 years ago
7 0
The queen-sized bed is your answer 
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A resistor, capacitor, and switch are all connected in series to an ideal battery of constant terminal voltage. Initially, the s
erma4kov [3.2K]

Answer:

The voltage across the resistor is zero, and the voltage across the capacitor is equal to the terminal voltage of the battery.

Explanation:

This is because when a capacitor is charged no current or voltage flows through it so it will have a voltage equal to the terminal voltage of the battery

6 0
4 years ago
g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh
Elan Coil [88]

Answer:

a) the propagation direction is x, b)   E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d)  f = 4.95 10¹¹ Hz, e)  λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

      E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

      E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

          E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

          C = E / B

          B = E / c

          B = 125/3 10⁸

          B = 41.67 10⁻⁸ T

d) the angular velocity is

          w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

          w = 2π f

           f = w / 2π

           f = 311.2 10¹¹ / 2π

           f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

          k = 2π /λ

          k = 14.2 10² rad / m

          λ = 2π / k

          λ = 2π / 14.2 10²

          λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

4 0
3 years ago
What are the benefits and harms of protists? WILL GIVE BRAINLIEST FOR THE PERFECT ANSWER
alina1380 [7]

Answer:

<em>Well, Many protists are harmful to humans, other animals and plants because they cause diseases and crop failures. However, some protists are actually beneficial to other creatures and are used by humans for various purposes. Plant-like protists produce almost one-half of the oxygen on the planet through photosynthesis. Other protists decompose and recycle nutrients that humans need to live. For example, medicines made from protists are used in treatment of high blood pressure, digestion problems, ulcers, and arthritis. Hope That Helps!</em>

<em>From ~Itsbrazts~. Have a Great Day!</em>

6 0
3 years ago
Read 2 more answers
Correct your friend that says, "The dragster rounded the curve at a constant velocity of 100 km/h." In other words, what is wron
Ainat [17]

Answer:

Correct statement will be dragster rounded the curve with constant speed

Explanation:

It is given that his fried says that The dragster rounded the curve with a constant velocity of 100 km/hour

It is a wrong statement because in circular motion velocity will never constant as the direction of speed is always changing

The correct statement will be dragster rounded the curve with a constant speed because speed may be constant in circular motion

8 0
3 years ago
A screen is placed 1.60 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 c
Lunna [17]

Answer:

distance between the two second-order minima is 2.8 cm

Explanation:

Given data

distance = 1.60 m

central maximum = 1.40 cm

first-order diffraction minima = 1.40 cm

to find out

distance between the two second-order minima

solution

we know that fringe width = first-order diffraction minima /2

fringe width = 1.40 /2 = 0.7 cm

and

we know fringe width of first order we calculate slit d

β1 = m1λD/d

d = m1λD/β1

and

fringe width of second order

β2 = m2λD/d

β2 = m2λD / ( m1λD/β1 )

β2 = ( m2 / m1 ) β1

we know the two first-order diffraction minima are separated by 1.40 cm

so

y = 2β2 = 2 ( m2 / m1 ) β1

put here value

y = 2 ( 2 / 1 ) 0.7

y = 2.8 cm

so distance between the two second-order minima is 2.8 cm

6 0
3 years ago
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