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Hoochie [10]
3 years ago
10

A Scientist was studying cockroach movement through a small passage. The scientist attached sandpaper to the inside surfaces of

the passage. Which variable was the scientist most likely trying to investigate?
A. weight
B. friction
C. temperature
D. energy transfer
Physics
1 answer:
diamong [38]3 years ago
8 0

Answer:

b

Explanation:

the cockroach was rubbing up against something

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taurus [48]

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Skills required to play floor hockey include passing, receiving passes, shooting, stick- handling (dribbling), defensive skills and goaltending. Players are allowed to use both sides of the blade of the stick. The front side is called the forehand (face) and the back side is called the backhand.

4 0
2 years ago
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What is the magnitude of the resultant of a 7.0-N force acting vertically upward and a 5.0-N force acting horizontally.
irakobra [83]

Answer:

Resultant force = 8.6N

Explanation:

Using Pythogorus' theorem

{a}^{2}  +  {b}^{2}  =  {c }^{2}  \\  {7}^{2}  +  {5}^{2}  =  {r}^{2} \\ 49 + 25 =  {r}^{2}  \\ 74 =  {r}^{2}  \\   \sqrt{74}  =   \sqrt{ {r }^{2} }  \\ 8.6 = r \\

Resultant force = 8.6N

6 0
2 years ago
Magnetic Energy density affected by area?​
Mademuasel [1]

Answer:

ya it is , affected!okay I think this

4 0
3 years ago
Suppose you first walk 12.0 m in a direction 20? west of north and then 20.0 m in a direction 40.0? south of west. how far are y
Gnesinka [82]
The representation of this problem is shown in Figure 1. So our goal is to find the vector \overrightarrow{R}. From the figure we know that:

\left | \overrightarrow{A} \right |=12m \\ \\ \left | \overrightarrow{B} \right |=20m \\ \\ \theta_{A}=20^{\circ} \\ \\ \theta_{B}=40^{\circ}

From geometry, we know that:

\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}

Then using vector decomposition into components:

For \ A: \\ \\ A_x=-\left | \overrightarrow{A} \right |sin\theta_A=-12sin(20^{\circ})=-4.10 \\ \\ A_y=\left | \overrightarrow{A} \right |cos\theta_A=12cos(20^{\circ})=11.27 \\ \\ \\ For \ B: \\ \\ B_x=-\left | \overrightarrow{B} \right |cos\theta_B=-20cos(40^{\circ})=-15.32 \\ \\ B_y=-\left | \overrightarrow{B} \right |sin\theta_B=-20sin(40^{\circ})=-12.85

Therefore:

R_x=A_x+B_x=-4.10-15.32=-19.42m \\ \\ R_y=A_y+B_y=11.27-12.85=-1.58m

So if you want to find out <span>how far are you from your starting point you need to know the magnitude of the vector \overrightarrow{R}, that is:
</span>
\left | \overrightarrow{R} \right |=&#10;\sqrt{R_x^2+R_y^2}=\sqrt{(-19.42)^2+(-1.58)^2}=\boxed{19.48m}

Finally, let's find the <span>compass direction of a line connecting your starting point to your final position. What we are looking for here is an angle that is shown in Figure 2 which is an angle defined with respect to the positive x-axis. Therefore:

</span>\theta_R=180^{\circ}+tan^{-1}(\frac{\left | R_y \right |}{\left | R_x \right |}) \\ \\ \theta_R=180^{\circ}+tan^{-1}(\frac{1.58}{19.42}) \\ \\ \theta_R=180^{\circ}+4.65^{\circ}=185.85^{\circ}


6 0
3 years ago
A piece of wood on top of an ocean wave stays in the same location, only moving up and down as the wave passes. It is energy tha
Ierofanga [76]

Answer:

Hey

Yes, this is true.

As some people have it wrong, waves in the water (ocean) are not waves of moving water, rather the wave is moving through the water. A wave is a disturbance of a medium not the meduim moving.

8 0
3 years ago
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