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TiliK225 [7]
3 years ago
10

Several years from now you have graduated with an engineering/physics degree and have been hired by a nanoengineering firm as an

intern. You have been assigned to work under a top engineer from the company. Their current project is to design a microscopic oscillator as a time keeping device. The engineering design involves placing a negative charge at the center of a very small positively charged metal ring. Your boss claims that the negative charge will undergo simple harmonic motion if displaced away from the center of the ring. Furthermore, they claim they can change the period (timing) of oscillation by adjusting the amount of charge on the ring. The first task they give you is to check the validity of their design.
a. Consider a charge −???? located a small distance z above the center of a positively charged ring with total charge +Q and radius R. Write an expression for the net force exerted on the charge −???? due to the ring of charge. What is the magnitude of the force on the charge −???? if it is at the location z = 0?

b. Use the binomial expansion as a mathematical tool to understand the motion of the charged particle under the assumption that it is only displaced a small distance z ≪ ???? away from the center of the ring. Using the binomial approximation, simplify your expression from part (a). You should have two terms in your expression for the net force.

c. Suppose that z =1.0 nanometer and R = 1.0 millimeter. Using these values, determine the relative strength of the force that each term in your expression contributes to the total force (calculate the ratio of z/R that appears in each term). Is one term negligible (i.e. is the value of one term very close to zero)?

d. Using results from part (c) show that the relevant force on charge −???? simplifies to a Hook’s law restoring force: ???? = −????x, where k is now a more complicated constant made up of several constants from this problem. What is k?

e. Using Newton’s 2nd Law, write down the differential equation of motion for the particle as it undergoes oscillations due to this Hook’s law force. Determine the period T of oscillations charge −???? makes about the equilibrium point z = 0 (this should not involve any calculations, see equations 15.32 and 15.37 from your book). Asses the validity of your solution by analyzing the physical units to make sure that your solution has units of time.
Physics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

See attached handwritten document for answer

Explanation:

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A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.
Mama L [17]

Answer: f_{r} = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

W_{x} = horizontal component of the weight = mgsinФ

W_{y} = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - f_{r} = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8m/s^{2}

f_{r} = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

v^{2} = u^{2} + 2aS

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}

we slot in a into the equation below to get frictional force

mgsinФ - f_{r} = ma

3 * 9.8 * sin 37 - f_{r} = 3* 0.4

17.9633 - f_{r} =  1.2

f_{r} = 17.9633 - 1.2

f_{r} = 16.49N

4 0
3 years ago
How does the "lollipop moment", exemplify for us the opportunity we all have to exercise leadership on a normal everyday basis?
Mrrafil [7]

Answer:

WHat do you mean by that

Explanation:

I dont get what you re asking

8 0
2 years ago
A ball is projected horizontally from the top of a hill with a velocity of 30m/s if it reaches the ground 5sec later the height
Vikki [24]

Answer:

The hill is a total of 150 meters tall

Explanation:

30×5=150

7 0
2 years ago
One of the largest barometers ever built was an oil-filled barometer constructed in Leicester, England in 1991. The oil had a he
ZanzabumX [31]

Answer:

ρ = 830.32 kg/m³

Explanation:

Given that

Oil head = 12.2 m

h= 12.2 m

Pressure P = 1.013 x 10⁵ Pa

Lets take density of the liquid =ρ

The pressure due to liquid P given as

P = ρ g h

Now by putting the all values in the above equation

1.013 x 10⁵ Pa = ρ x 10 x 12.2                 ( take g =10 m/s²)

ρ = 830.32 kg/m³

Therefore the density of oil is 830.32  kg/m³

5 0
3 years ago
1. ¿Cuál es el actor clave de del exceso de peso corporal?
Slav-nsk [51]

El factor mas importante para el exceso de peso es un  exceso de energía creada por una alimentación excesiva

El peso de un cuerpo es definido por la relación entre la energía requerida para los procesos vitales del cuerpo, sus actividades físicas diarias y la energía suministra en forma de alimentos.

Cuando estos dos parámetros están en balance el peso es estable, pero cuando la cantidad de alimentos aumenta o el valor energético de los mismo aumenta se tiene un exceso de energía que el cuerpo almacena en forma de grasa corporal, este el el factor mas importante para el exceso de peso.

En conclusión el factor mas importante para el exceso de peso es un  exceso de energía por una alimentación excesiva

aprende mas acerca del peso corporal aquí:

brainly.com/question/13032223

8 0
2 years ago
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