Answer:
9.6m/s
Explanation:
Using the equation S=d/t where s=speed, d=distance, and t=time
plug in the known variables
S=120m/12.5s
S=9.6m/s
Answer:
v = 1.30 m/s
Explanation:
given,
mass hung = 0.35 Kg
spring stretched when load is hanged (x)= 0.13 m
now,
weight of the mass attached = Kx
m g = k x
0.35 x 9.8 = k x 0.13
k = 26.38 N/m
now, using conservation of energy




v = 1.30 m/s
1.A
2. C
3. Not Sure
4. Not Sure
5. Biometrics can help to identify
who's at risk for injuries and when
they're able to safely return, and
they can gauge athlete readiness to
determine when they'll be
performing at an optimal level.
The coefficient of linear expansion, given that the length of the pipe increased by 1.5 cm is 1.67×10¯⁵ /°F
<h3>How to determine the coefficient of linear expansion</h3>
From the question given above, the following data were obtained
- Original diameter (L₁) = 10 m
- Change in length (∆L) = 1.5 cm = 1.5 / 100 = 0.015 m
- Change in temperature (∆T) = 90 °F
- Coefficient of linear expansion (α) =?
The coefficient of linear expansion can be obtained as illustrated below:
α = ∆L / L₁∆T
α = 0.015 / (10 × 90)
α = 0.015 / 900
α = 1.67×10¯⁵ /°F
Thus, we can conclude that the coefficient of linear expansion is 1.67×10¯⁵ /°F
Learn more about coefficient of linear expansion:
brainly.com/question/28293570
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