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zepelin [54]
3 years ago
8

The luxury liner Queen Elizabeth 2 has a diesel-electric powerplant with a maximum power of 90 MW at a cruising speed of 31.5 kn

ots. What forward force is exerted on the ship at this highest attainable speed? (1 knot = 0.514 m/s. MW = Megawatts)
Physics
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:

5558643.69 N

Explanation:

F = Force

v = Velocity = 31.5 knots

Converting to m/s

1\ knot=0.514\ m/s

31.5\ knot=31.5\times 0.514\ m/s=16.191\ m/s

Power is given by

P=Fv\\\Rightarrow F=\frac{P}{v}\\\Rightarrow F=\frac{90\times 10^6}{16.191}\\\Rightarrow F=5558643.69\ N

The forward force is exerted on the ship at this highest attainable speed is 5558643.69 N

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correct me if I'm wrong

4 0
2 years ago
A 60 kg acrobat is in the middle of a 10 m long tightrope. The center of the rope dropped 30 cm in relation to the ends that are
Zigmanuir [339]

Answer:

The tension in each half of the rope, is approximately 4,908.8 N

Explanation:

The mass of the acrobat, m = 60 kg

The length of the rope, l = 10 m

The extent by which the center dropped = 30 cm = 0.3 m

Let, 'T' represent the tension in each half of the rope

Weight, W = Mass, m × The acceleration due to gravity, g

∴ W = m × g

The acceleration due to gravity, g ≈ 9.8 m/s²

∴ The weight of the acrobat, W = 60 kg × 9.8 m/s² ≈ 588 N

The angle the dropped rope makes with the horizontal, θ is given as follows;

θ = arctan((0.3 m)/(5 m)) = arctan(0.06) ≈ 3.434°

At equilibrium, the sum of vertical forces, \Sigma F_y = 0

The vertical component of the tension, T_y, in each half of the rope is given as follows;

T_y = T × sin(θ)

∴ \Sigma F_y = W + T × sin(θ) + T × sin(θ) = W + 2 × T × sin(θ)

Plugging in the values, with θ = arctan(0.06) for accuracy, we get;

588 N + 2 × T × sin(arctan(0.06) = 0

∴ 2 × -T × sin(arctan(0.06) = 588 N

-T= 588 N/(2 × sin(arctan(0.06)) = 4,908.81208 N ≈ 4,908.8 N

The tension in each half of the rope, T ≈ 4,908.8 N.

4 0
2 years ago
A volleyball is dropped from a cliff and a soccer ball is thrown upward from the same position. When each ball reaches the groun
vredina [299]
The question is whether the statement is true or false.

The answer if false.

Explanation:

It is exactly the opposite. The soccer ball will hit the ground with greater velocity.

Since the soccer ball is thrown upward, when it returns to the same heigth from which it was throwm it will have a velocity downward, which will make that the soocer ball reaches the ground at the bottom of the clif with greater velocity than the volleball.

The greater the velocity with which the soccer ball is thrown upward, the greater its velocity when reaches the same point from which it was thrown, and the greater the velocity with which it will hit the ground at the bottom of the clif.
6 0
3 years ago
Can someone help me with this question
Anna71 [15]

Answer:

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7 0
2 years ago
Leoni is participating in four drawing competitions. If the probability of her losing any
Alex17521 [72]

Answer:

(a) Probability = 0.7599

(b) Probability = 0.2646

Explanation:

Represent losing with L and winning with W.

So:

L = 0.7 --- Given

n = 4

Probability of winning would be:

W = 1 - L

W = 1 - 0.7

W = 0.3

The question illustrates binomial probability and will be solved using the following binomial expansion;

(L + W)^4 = L^4 + 4L^3W + 6L^2W^2 + 4LW^3 + W^4

So:

Solving (a): Winning at least 1

We look at the above and we list out the terms where the powers of W is at least 1; i.e., 1,2,3 and 4

So, we have:

Probability = 4L^3W + 6L^2W^2 + 4LW^3 + W^4

Substitute value for W and L

Probability = 4 * 0.7^3*0.3 + 6*0.7^2*0.3^2 + 4*0.7*0.3^3 + 0.3^4

Probability = 0.7599

<em>Hence, the probability of her winning at least one is 0.7599</em>

Solving (a): Wining exactly 2

We look at the above and we list out the terms where the powers of W is exactly 2

So, we have:

Probability = 6L^2W^2

Substitute value for W and L

Probability = 6*0.7^2*0.3^2

Probability = 0.2646

<em>Hence, the probability of her winning exactly two is 0.2646</em>

6 0
2 years ago
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