Distance of fall from rest,
without air resistance = (1/2) (gravity) (time)²
= (1/2) (9.8 m/s²) (95 sec)²
= (4.9 m/s²) (9,025 sec²)
= 44,222.5 meters .
The depth of the mine shaft is five times the height of Mt. Everest !
Answer:
P.E. = -0.449 J
Explanation:
Potential energy of a charge particle in any electrostatic field is defined as the amount of work done ( in negative ) to bring that charge particle from any position to a new position r.
Now Potential energy is defined by this formula,
P.E. = k q₁ q₂/ r
where P.E. is the potential energy.
k = 1/( 4πε₀) = 8.99 × 10⁹ C²/ ( Nm²)
q₁ = charge of one particle = +1.0μC
q₂ = charge of another particle = -5.0μC
r = distance = 0.1 m
Now , P.E. = 8.99 × 10⁹C²/ ( Nm²) * ( -5.0 × 10⁻⁶ C ) × ( 1 × 10⁻⁶ C ) / 0.1 m
P.E. = -0.449 J
<span>Answer:
sin(incidence)/sin(refraction) = n_refraction/n_incidence
sin(50) / sin(x) = 1.5 / 1
sin(50)/1.5 = sin(x)
sin(x) = 0.511
x = 30.71o
B]
50 degrees, same as the angle going in.
You can show that by reversing the steps in A.
sin(30.7)/sin(x) = 1/1.5
C]
The glass is 5 cm thick.
The reference angle = 30.7o
Tan(30.7) = displacement / thickness
Tan(30.7) = x / 5
5*sin(30.7) = x
x = 2.97 cm which is the displacement.</span>
By <span> It is directly proportional to the </span>average kinetic energy<span>.</span>
Answer:
The boat will be 74 .17 meters downstream by the time it reaches the shore.
Explanation:
Consider the vector diagrams for velocity and distance shown below.
converting 72 miles per hour to km/hr
we have 72 miles per hour 72 × 1.60934 = 115.83 km/hr
The velocity vectors form a right angled triangle, and can be solved using simple trigonometric laws
This is the vector angle with which the ship drifts away with respect to its northward direction.
<em>From the sketch of the displacement vectors, we can use trigonometric ratios to determine the distance the boat moves downstream.</em>
Let x be the distance the boat moves downstream.d
∴The boat will be 74 .17 meters downstream by the time it reaches the shore.
