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OLEGan [10]
3 years ago
5

An electron moving in the direction of the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in

the -y direction, the direction of the magnetic field in this region points in the direction of the An electron moving in the direction of the +-axis enters a magnetic field. If the electron experiences a magnetic deflection in the - direction, the direction of the magnetic field in this region points in the direction of the a. -y-axis. b. -z-axis. c. -x-axis. d. +z-axis. e. +y-axis.
Physics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

<h2>As per right hand rule the force direction magnetic field is along - z axis</h2>

Explanation:

As we know that the force on the moving charge due to magnetic field is given as

\vec F = q(\vec v \times \vec B)

here we know that

\vec v = v\hat i

q = - e

\vec F = F (-\hat j)

so we will have

F(-\hat j) = (-e)(v (\hat i) \times \vec B)

so direction of magnetic field must be along -Z Axis

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A person of mass m will bungee-jump from a bridge over a river where the height from the bridge to the river is h. The bungee co
Likurg_2 [28]

Answer:k_{min}=\frac{18mg}{h}

Explanation:

Given

mass of person is m

Distance between bridge and river is h

chord has an un-stretched length of \frac{2h}{3}

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Person will just stop before hitting the river

Conserve energy i.e. Potential Energy of Person is converted in to elastic energy of chord

mgh=\frac{kx^2}{2}

x=h-\frac{2h}{3}=\frac{h}{3}

mgh=\frac{kh^2}{18}

k=\frac{18mg}{h}

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4 years ago
Bryan Allen pedaled a human-powered aircraft across the English Channel from the cliffs of Dover to Cap Gris-Nez on June 12, 197
Leno4ka [110]

(a) 3.58 km 45° south of east

The total displacement is given by:

d=vt

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v is the average velocity

t is the time

The average velocity is:

v = 3.53 m/s

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t=169 min \cdot 60 s/min = 10140 s

Therefore, the magnitude of the displacement is

d=(3.53)(10140)=35794 m = 3.58 km

And the direction is the same as the velocity, therefore 45° south of east.

(b) 5.53 m/s 90° south of east

The velocity of the air relative to the ground is

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and the direction is exactly opposite to that of Allen, so it is 45° north of west. Allen's velocity relative to the ground is

v = 3.53 m/s

So this must be the resultant of Allen's velocity relative to the air (v') and the air's speed (v_a). Since these two vectors are in opposite direction, we have

v= v'-v_a

Therefore we find v', Allen's velocity relative to the air:

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The direction must be measured relative to the air's reference frame. In this reference frame, Allen is moving exactly backward, so his direction will be 90° south of east.

(c) 56.1 km at 90° south of east.

Since Allen's velocity relative to the air is

v' = 5.53 m/s

Then the displacement of Allen relative to the air will be given by

d'=v't

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d'=(5.53)(10140)=56074 m = 56.1 km

And the direction is the same as that of the velocity, therefore will be 90° south of east.

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3 years ago
PLZ HELP ME Which are not correct statements?
AURORKA [14]
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F.r.e.e points :]]] ​
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