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Simora [160]
3 years ago
13

Two objects exert a gravitational force of 3 N on one another when they are 10 m apart. What would that force be if the distance

between the two objects were reduced to 5 m?
A. 1.5 N
B. 6 N
C. 12 N
D. 24 N
Physics
1 answer:
jeka943 years ago
8 0
Gravitational force = G ( m1 m2 ) / r²
3 = G ( m1 m2 ) / ( 10 )²x = G ( m1 m2 ) / ( 5 )²We shall divide those two equations:3 / x = 1/100 / 1/25 = 25 / 100 = 1 / 4x · 1 = 3 · 4x = 12Answer:C. 12 N
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You're driving your new sports car at 85 mph over the top of a hill that has a radius of curvature of 525 m.
Bumek [7]

Explanation:

It is given that,

Speed of the sports car, v = 85 mph = 37.99 m/s

The radius of curvature, r = 525 m

Let W_N is the normal weight and W_A is the apparent weight of the person. Its apparent weight is given by :

W_A=mg-\dfrac{mv^2}{r}

So, \dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}

\dfrac{W_A}{W_N}=\dfrac{g-\dfrac{v^2}{r}}{g}

\dfrac{W_A}{W_N}=\dfrac{9.8-\dfrac{(37.99)^2}{525}}{9.8}

\dfrac{W_A}{W_N}=0.719

or

\dfrac{W_A}{W_N}=71.9\%

Hence, this is the required solution.

5 0
3 years ago
The distance between two slits is 1.50 *10-5 m. A beam of coherent light of wavelength 600 nm illuminates these slits, and the d
Fed [463]

Answer: y = 2.4×10^-6m or y= 2.4μm

Explanation: The formulae for the distance between the central bright fringe to any other fringe in pattern is given as

y = R×mλ/d

Where y = distance between nth fringe and Central bright spot fringe.

m = position of fringe = 4

λ = wavelength of light= 600nm = 600×10^-9 m

d = distance between slits = 1.50×10^-5m

R = distance between slit and screen = 2m

y = 2 × 4 × 600×10^-9/2

y = 4800×10^-9/2

y = 2400 × 10^-9

y = 2.4×10^-6m or y= 2.4μm

8 0
3 years ago
(Mass vs. Weight) HELP PLZ!!
Lina20 [59]

\huge \boxed { \sf{Answers}}

  • c. The weight of an object on the moon will be the same as its weight on Earth. It is false because the weight of an on the moon will be 1/6 th times its weight on Earth.
  • d. The weight of an object is its mass multiplied by the force of gravity. The statement is false because the formula of weight is mass × acceleration due to gravity, not force of gravity.
  • e. The mass and weight of an object are the same thing. The statement is false because mass means a body of matter. While weight of an object is its mass multiplied by the force of gravity.
  • f. The mass of an object is the force of gravity acting upon an object. It is false because it will be the weight of the object not mass.
  • So, the answers are c, d, e and f.

Hope you could understand.

If you have any query, feel free to ask.

7 0
3 years ago
According to Newton's first law, which characteristic of a moving object would remain constant if there were no other
suter [353]
In object in motion stays in motion; speed
8 0
3 years ago
Sound with frequency 1300 Hz leaves a room through a doorway with a width of 1.03 m . At what minimum angle relative to the cent
AlexFokin [52]

Answer:

  about 14.7°

Explanation:

The formula for the angle of the first minimum is ...

  sin(θ) = λ/a

where θ is the angle relative to the door centerline, λ is the wavelength of the sound, and "a" is the width of the door.

The wavelength of the sound is the speed of sound divided by the frequency:

  λ = (340 m/s)/(1300 Hz) ≈ 0.261538 m

Then the angle of interest is ...

  θ = arcsin(0.261538/1.03) ≈ 14.7°

At an angle of about 14.7°, someone outside the room will hear no sound.

6 0
3 years ago
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