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3 years ago

Example of nuclear fission and nuclear fusion

Physics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium.

Explanation:

I hope this helped you

(Sorry If it didn't)

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If a magnet repels a metal object what can you say about the pole of the magnet and the pole of the object?

sleet_krkn [62]

Poles are the same D is the right answer

7 0

3 years ago

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A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0s. How strong must the rope be? μk

Leokris [45]

Answer:

The rope must have a force of 10084,21 N

Explanation

Acceleration calculation

The car acceleration is equal to the acceleration of the truck

ac: car acceleration $\frac{m}{s^{2} }$

at: truck acceleration $\frac{m}{s^{2} }$ )

$ac = at= \frac{vf-vi}{t-ti}$ equation(1)

Known information:

vi = Initial speed = 0, ti = initial time = 0

vf = Final speed = 13 $\frac{m}{s}$ , t = final time =5 s

We replaced the known information in the equation(1):

$ac = at = \frac{13-0}{15-0}$

$ac=ac=\frac{13}{15} \frac{m}{s}$

Dynamic analysis

The forces acting on the car are the following:

Wc: Car weight

N: normal force, road force on the car

Ff: Friction force

T: Force of tension

Car weight calculation:

$Wc=mc*g$

mc = Car mass = 2230kg

g = Gravity acceleration=9.8 $\frac{m}{s^{2} }$

$Wc= 2230*9.8$

$Wc=21854 N$

Normal force calculation:

Newton's first law

$sum Fy= 0$

$N-W=0$

$N=W$

$N=21854 N$

Friction force calculation (Ff):

We have the formula to calculate the friction force:

Ff = μk * N Equation (3)

μk kinetic coefficient of friction

We know that μk = 0.373and N= 21854N ,then:

$Ff=0.373*21854$

$Ff=8151.54 N$

Calculation of the tension force in the rope (T):

Newton's Second law

$sum Fx= mc*ac$

$T-Ff=mc*ac$

$T=2230(\frac{13}{15}) + 8151.54$

T=10084,21 N

Answer: The rope must have a force of 10084,21 N

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3 years ago

A force of 20N pushes an object of mass 5.0kg along a rough surface of 5.0N

Alika [10]

Answer:

I'm sorry, I don't think there is any answer to give seeing as no question has been asked

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3 years ago

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An ocean wave traveling in one direction has a wavelength of 1.0 m and a frequency of 1.25 Hz. Take the direction of wave propag

aliina [53]

Answer:

a) $v=1*1.25=1.25\: m/s$

b) $y(x,t)=2sin(2\pi( x-1.25 t)$

c) $y(3,10)=1.73 m$

Explanation:

a) The speed of a wave is given by the following equation:

$v=\lambda f$

Where:

λ is the wavelength

f is the frequency

$v=1*1.25=1.25\: m/s$

b) The harmonic wave has the following equation:

$y=Asin(kx-\omega t)$

A is the amplitude (2 m)

k is the wavenumber (2π/λ)

ω is the angular frequency (2πf)

$y(x,t)=2sin(2\pi x-2\pi*1.25 t)$

$y(x,t)=2sin(2\pi( x-1.25 t)$

c) Here we need to find the heigth at x=3 m and t =10 s, so we need to find y(3,10).

$y(3,10)=2sin(2\pi(3-1.25*10)$

$y(3,10)=1.73 m$

I hope it helps you!

6 0

3 years ago

In example 18. 4 of the text, the deflection angle of the laser beam as it exits the prism is 22. 6º. If the prism had been made

Marrrta [24]

The deflection angle is 37.29º if the prism was made of polystyrene plastic.

What is a laser beam?

Laser beam is a light beam propagating dominantly in one direction.

It is a beam of radiation produced from a laser.

Here given that,

refraction index of glass, n1= 1.52

refraction index of polystyrene plastic, n2 = 1.59

deflection angle, B = 22.6º

For the second surface,

B = 45º - 22.6º

B = 22.40º

Now from the formula of Snell's law:

n1 sinФ = n2 sin B

sin B / sinФ = n1 / n2

sinФ = (sin 22.40º) * ( 1/ 1.59)

Ф = 37.29º

Hence,

The deflection angle is 37.29º if the prism was made of polystyrene plastic.

Learn more about laser beam here:

<u>brainly.com/question/4218151</u>

#SPJ4

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2 years ago

Example of nuclear fission and nuclear fusion​

Example of nuclear fission and nuclear fusion