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Tcecarenko [31]
2 years ago
6

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
2 answers:
GarryVolchara [31]2 years ago
3 0

I'm in physics, but I think the answer is 22. The angle of reflection is reflecting whatever the angle was so, in this case, it must be 22

const2013 [10]2 years ago
3 0

Answer:The angle reflection will be 22 degrees.

Explanation:

Reflection: The bouncing back of light rays from the shiny surface is termed as reflection.

Laws of reflection:

  • Incident ray , reflected ray and normal drawn perpendicularly to the surface of the shiny surface all lie in the same plane.
  • Angle of incidence is equal to the angle of reflection.

So, if the angle of an incidence is 22 degrees than the angle of reflection will also be the same as 22 degrees.

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A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the
Shkiper50 [21]

Answer:

 ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round  = 144 Kg

angle =  33.2°

moment of inertia

I = \dfrac{1}{2} m R^2

I = \dfrac{1}{2}\times 144 \times 2.75^2

    I = 544.5 kg.m²

torque = force  x radius

τ = 37.7 x  2.75

τ = 103.675 N.m

angular acceleration

\alpha= \dfrac{\tau}{I}

\alpha= \dfrac{103.675}{544.5}

 α = 0.190 rad/s²

now ,

distance = 33.2\times \dfrca{2\pi}{360}

d = 0.579 rad

we know,

using equation of rotational motion

d = \omega t + \dfrac{1}{2}\alpha t^2

0.579 = \dfrac{1}{2}\times 0.190\times t^2

 t = 2.46 s

angular speed

 ω =  α  x t

 ω = 0.19 x 2.46

 ω = 0.467 rad/s

7 0
2 years ago
How much heat do you need to raise the temperature of 150 g of oxygen from -30c to -15c?
Naddika [18.5K]
The amount of heat needed to raise the temperature of a substance by \Delta T is given by
Q=m C_s \Delta T
where
m is the mass of the substance
Cs is its specific heat capacity
\Delta T is the increase in temperature

For oxygen, the specific heat capacity is approximately 
C_s = 0.92 J/(g K)
The variation of temperature for the sample in our problem is 
\Delta T= -15^{\circ}C-(-30^{\circ} C)=+15^{\circ}C=15 K
while the mass is m=150 g, so the amount of heat needed is
Q=m C_s \Delta T=(150 g)(0.92 J/g K)(15 K)=2070 J
4 0
3 years ago
Read 2 more answers
9. If the musician hit the drum on a stage, how would the sound wave behave differently if he hit it the drum if the drum were s
egoroff_w [7]
I think it would be yes because the drum is submerged in water and the water would slow the sound waves, making the sound softer. Right?
4 0
3 years ago
If your friend drops a chocolate bar to you from a height of 5.0 m above your hands,
Sladkaya [172]

Answer:

<h3>1.01 s</h3>

Explanation:

Using the equation of motion S = ut+1/2gt² to solve the problem where;

u is the initial velocity of the chocolate = 0m/s

t is the time taken

g is the acceleration due to gravity = 9.81m/s²

S is the height of fall = 5.0m

Substituting the given parameter into the formula to get the time t we have;

5 = 0(t)+1/2(9.81)t²

5 = 4.905t²

t² = 5/4.905

t² = 1.019

t = √1.019

t = 1.009 secs

<em>Hence it will take 1.01 secs for me to catch the chocolate bar</em>

6 0
3 years ago
Please help! What are 3 things that make Longitudinal and Transverse waves the same?
Flura [38]
"<span>All waves have frequency, wavelength, speed and amplitude." </span>
4 0
3 years ago
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