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siniylev [52]
3 years ago
6

3. The velocity of sound is 332 m/s. Answer the following questions:

Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

20 Hz, 20000 Hz

0.0166 m, 16.6 m

Explanation:

The minimum frequency that a human ear can hear is 20 Hz

The maximum frequency that a human ear can hear is 20000 Hz.

v = Velocity of sound = 332 m/s

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}

The longest wavelength that can be heard by the human ear is 16.6 m

\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}

The shortest wavelength that can be heard by the human ear is 0.0166 m.

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A parallel plate capacitor is connected to a DC battery supplying a constant DC voltage V0= 600V via a resistor R=1845MΩ. The ba
tensa zangetsu [6.8K]

Answer:

See explanation

Explanation:

Given:-

- The DC power supply, Vo = 600 V

- The resistor, R = 1845 MΩ

- The plate area, A = 58.3 cm^2

- Left plate , ground, V = 0

- The right plate, positive potential.

- The distance between the two plates, D = 0.3 m

- The mass of the charge, m = 0.4 g

- The charge, q = 3*10^-5 C

- The point C = ( 0.25 , 12 )

- The point A = ( 0.05 , 12 )

Find:-

What is the speed, v, of that charge when it reaches point A(0.05,12)?

How long would it take the charge to reach point A?

Solution:-

- The Electric field strength ( E ) between the capacitor plates, can be evaluated by the potential difference ( Vo ) of the Dc power supply.

                           E = Vo / D

                           E = 600 / 0.3

                           E = 2,000 V / m

- The electrostatic force (Fe) experienced by the charge placed at point C, can be evaluated:

                           Fe = E*q

                           Fe = (2,000 V / m) * ( 3*10^-5 C)

                           Fe = 0.06 N

- Assuming the gravitational forces ( Weight of the particle ) to be insignificant. The motion of the particle is only in "x" direction under the influence of Electric force (Fe). Apply Newton's equation of motion:

                          Fnet = m*a

Where, a : The acceleration of the object/particle.

- The only unbalanced force acting on the particle is (Fe):

                          Fe = m*a

                          a = Fe / m

                          a = 0.06 / 0.0004

                          a = 150 m/s^2

- The particle has a constant acceleration ( a = 150 m/s^2 ). Now the distance between (s) between two points is:

                         s = C - A

                         s = ( 0.25 , 12 ) - ( 0.05 , 12 )

                         s = 0.2 m

- The particle was placed at point C; hence, velocity vi = 0 m/s. Then the velocity at point A would be vf. The particle accelerates under the influence of electric field. Using third equation of motion, evaluate (vf) at point A:

                        vf^2 = vi^2 + 2*a*s

                        vf^2 = 0 + 2*0.2*150

                        vf = √60

                        vf = 7.746 m/s

- Now, use the first equation of motion to determine the time taken (t) by particle to reach point A:

                       vf - vi = a*t

                       t = ( 7.746 - 0 ) / 150

                       t = 0.0516 s

- The charge placed at point C, the Dc power supply is connected across the capacitor plates. The capacitor starts to charge at a certain rate with respect to time (t). The charge (Q) at time t is given by:

                      Q = c*Vo*[ 1 - e^(^-^t^/^R^C^)]

- Where, The constant c : The capacitance of the capacitor.

- The Electric field strength (E) across the plates; hence, the electrostatic force ( Fe ) is also a function of time:

                     E = \frac{Vo*[ 1 - e^(^-^t^/^R^C^)]}{D} \\\\Fe = \frac{Vo*[ 1 - e^(^-^t^/^R^C^)]}{D}*q\\\\

- Again, apply the Newton's second law of motion and determine the acceleration (a):

                     Fe = m*a

                     a = Fe / m

                     a = \frac{Vo*q*[ 1 - e^(^-^t^/^R^C^)]}{m*D}

- Where the acceleration is rate of change of velocity "dv/dt":

                     \frac{dv}{dt}  = \frac{Vo*q}{m*D}  - \frac{Vo*q*[ e^(^-^t^/^R^C^)]}{m*D}\\\\B =  \frac{600*3*10^-^5}{0.0004*0.3} = 150, \\\\\frac{dv}{dt}  = 150*( 1 - [ e^(^-^t^/^R^C^)])\\\\

- Where the capacitance (c) for a parallel plate capacitor can be determined from the following equation:

                      c = \frac{A*eo}{d}

Where, eo = 8.854 * 10^-12  .... permittivity of free space.

                     K = \frac{1}{RC}  = \frac{D}{R*A*eo} =  \frac{0.3}{1845*58.3*8.854*10^-^1^2*1000} = 315\\\\

- The differential equation turns out ot be:

                     \frac{dv}{dt}  = 150*( 1 - [ e^(^-^K^t^)]) = 150*( 1 - [ e^(^-^3^1^5^t^)]) \\\\

- Separate the variables the integrate over the interval :

                    t : ( 0 , t )

                    v : ( 0 , vf )

Therefore,

                   \int\limits^v_0 {dv} \,  = \int\limits^t_0 {150*( 1 - [ e^(^-^3^1^5^t^)])} .dt \\\\\\vf  = 150*( t + \frac{e^(^-^3^1^5^t^)}{315} )^t_0\\\\vf = 150*( t + \frac{e^(^-^3^1^5^t^) - 1}{315}  )

- The final velocity at point A for the particle is given by the expression derived above. So for t = 0.0516 s, The final velocity would be:

                    vf = 150*( 0.0516 + \frac{e^(^-^3^1^5^*^0^.^0^5^1^6^) - 1}{315}  )\\\\vf = 7.264 m/s

- The final velocity of particle while charging the capacitor would be:

                   vf = 7.264 m/s ... slightly less for the fully charged capacitor

                     

7 0
3 years ago
Object A and object B are 10 m apart. Which of the following will cause the greatest increase in gravitational force between the
lianna [129]
<span>4)Increase the mass of both object A and object B. </span>
7 0
4 years ago
Read 2 more answers
Find the wavelength of the third line in the lyman series, and identify the type of em radiation.
Natalija [7]

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( \frac{1}{(n1)^{2} } -   \frac{1}{(n2)^{2} })

                 = 109678 ( \frac{1}{1^{2} } -  \frac{1}{3^{2} } )

                 = 109678 (8/9)

   Lambda = 9 / (109678 * 8 )

                  = 102.6 * 10^{-9} m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

#SPJ4

8 0
2 years ago
Electricity from the local power company costs 5.79 cents/kWh. How much would it cost to run a 120-W stereo system for 4.0 hours
xenn [34]

Answer:

<em>Answer: B. $0.78.</em>

Explanation:

<u>Cost of Electricity </u>

The rate of the cost of electricity is usually expressed in $/kWh or cents/kWh because the consumption of electricity is measured in Kilowatts-hour.

The local power company charges 5.79 cents/kWh.

We are required to calculate the cost to run a 120 W stereo system for 4 hours per day for 4 weeks.

The total consumption time is 4 hours/day * 7 days/week *4 weeks = 112 hours

The total energy consumed is 120 W * 112 h =13,440 Wh.

Converting to kWh: 13,440 Wh/1,000 = 13.440 kWh.

Finally, we multiply by the cost rate: 5.79 cents/kWh * 13.440 kWh = 77.8 cents/100 = $0.78.

Answer: B. $0.78.

3 0
3 years ago
which observation about the Mid-Atlantic Ridge region provides the best evidence of the seafloor has been spreading over for mil
Kitty [74]

Magnetic stripes on the sea floor

Explanation:

The observation of magnetic stripes patterns at the region of the Mid-Atlantic Ridge galvanized the evidence that sea floor spreading has been on for several millions of years.

  • Geomagnetic field of the earth is similar to that of bar magnet having the north and south pole.
  • It originates from the movement of iron-nickel within the outer core.
  • This geomagnetic field causes the magnetization of magnetic minerals in rock.
  • When freshly formed magma is brought to the surface at the mid oceanic ridge area, the prevailing magnetic field causes the magnetic minerals in the magma to cool in such a way that they align their domains to that of the field.
  • The magnetic field of the earth can reverse and take different geometry. Sometimes, its intensity is very strong and at other times it is weak.
  • The magnetic minerals in melts bear these records.
  • As new materials are brought up, they get magnetized.

Learn more:

Sea floor spreading brainly.com/question/9912731

#learnwithBrainly

8 0
3 years ago
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