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siniylev [52]
3 years ago
6

3. The velocity of sound is 332 m/s. Answer the following questions:

Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

20 Hz, 20000 Hz

0.0166 m, 16.6 m

Explanation:

The minimum frequency that a human ear can hear is 20 Hz

The maximum frequency that a human ear can hear is 20000 Hz.

v = Velocity of sound = 332 m/s

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}

The longest wavelength that can be heard by the human ear is 16.6 m

\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}

The shortest wavelength that can be heard by the human ear is 0.0166 m.

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Explanation:

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How many electrons are contained on the negatively-charged side of a capacitor when it is fullycharged if it is connected to a 1
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Answer:

Explanation:

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C = ε₀ A / d

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Charge = capacitance x volt

= .553125 x 10⁻¹³ x 1.5

= .8296875 x 10⁻¹³ C

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Which statement correctly explains molecular motion in different states of matter using the kinetic theory?
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the answer is the second one

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3 years ago
A straight wire lies along the y-axis initially carrying a current of 10 A in the positive y-direction. The current decreases an
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The magnetic field due to straight wire is into the square coil.

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8 0
4 years ago
An insulating cup contains 200 grams of water at 25 ∘C. Some ice cubes at 0 ∘C is placed in the water. The system comes to equil
Nataly [62]

Answer:

The amount of ice added in gram is 32.77g

Explanation:

This problem bothers on the heat capacity of materials

Given data

Mass of water Mw= 200g

Temperature of water θw= 25°c

Temperature of ice θice= 0°c

Equilibrium Temperature θe= 12°c

Mass of ice Mi=???

The specific heat of ice Ci= 2090 J/(kg ∘C)

specific heat of water Cw = 4186 J/(kg ∘C)

latent heat of the ice to water transition Li= 3.33 x10^5 J/kg

heat heat loss by water = heat gained by ice

N/B let us understand something, heat gained by ice is in two phases

Heat require to melt ice at 0°C to water at 0°C

And the heat required to take water from 0°C to equilibrium temperature

Hence

MwCwΔθ=MiLi +MiCiΔθ

Substituting our data we have

200*4186*(25-12)=Mi*3.3x10^5+

Mi*2090(12-0)

837200*13=Mi*3.3x10^5+Mi*2090

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Mi= 32.77g

4 0
4 years ago
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