The average atomic mass of Sn is 118.71 g/mol
the percentage of heaviest Sn is 5.80%
the given mass of Sn is 82g
The total moles of Sn will be = mass / atomic mass = 82/118.71=0.691
Total atoms of Sn in 82g = 
the percentage of heaviest Sn is 5.80%
So the total atoms of 
= 5.80% X 
Total atoms of =
atoms
the mass of will be = 
All of the above answers are true right answer is option D
because, no bond no molecule no interaction no life,
no bond= only element will exist
Energy would not exist coz energy consumption and excretion takes place during bond formation and bond breaking process!
Answer:
4.43 g of Oxygen
Explanation:
As shown in Chemical Formula, one mole of Aluminium Sulfate [Al₂(SO₄)₃] contains;
2 Moles of Aluminium
3 Moles of Sulfur
12 Moles of Oxygen
Also, the Molar Mass of Aluminium Sulfate is 342.15 g/mol. It means,
342.15 g ( 1 mole) of Al₂(SO₄)₃ contains = 192 g (12 mole) of O
So,
7.9 g of Al₂(SO₄)₃ will contain = X g of O
Solving for X,
X = (7.9 g × 192 g) ÷ 342.15 g
X = 4.43 g of Oxygen
Answer : The isoelectronic groups are:
Explanation :
Isoelectronic : It is defined as the compound or molecule having the same number of electrons and the same number of electronic structure.
- The element is helium. The number of electrons are 2.
- The element is beryllium. The number of electrons are 4. The number of electrons in
= 4 - 2 = 2 - The element is lithium. The number of electrons are 3. The number of electrons in
= 3 - 1 = 2 - The element is nitrogen. The number of electrons are 7. The number of electrons in
= 7 + 3 = 10 - The element is neon. The number of electrons are 10.
- The element is sulfur. The number of electrons are 16. The number of electrons in
= 16 + 2 = 18 - The element is magnesium. The number of electrons are 12. The number of electrons in
= 12 - 2 = 10 - The element is titanium. The number of electrons are 22. The number of electrons in
= 22 - 4 = 18 - The element is potassium. The number of electrons are 19. The number of electrons in
= 19 - 1 = 18
The isoelectronic groups are:
Answer:
10.8amu
Explanation:
Given parameters:
Abundance of B - 10 = 20% = 0.2
Abundance of B - 11 = 80% = 0.8
Unknown:
Atomic mass of Boron = ?
Solution:
The atomic mass of Boron can be can be calculated using the expression below;
Atomic mass = (abundance of B - 10 x mass of isotope B - 10 ) +( abundance of B - 11 x mass of isotope B- 11)
Atomic mass = (0.2 x 10) + (0.8 x 11) = 2 + 8.8 = 10.8amu
