Answer:
Acceleration = -12/17 m/s ^2
Explanation:
<u><em>Name the variables</em></u>
<em>V </em>= final velocity( velocity after the train stops) u= intial velocity(velocity when the train was moving at constant speed, before brakes are applied)
<em>A</em> = acceleration( in this case, it is deceleration)
<em>T</em> = time ( time taken to fully stop)
<em>Second Step:</em> What equation should we use?
The 3 Big Motion in One Dimension Formulas are:
<em>V</em> = u+at
v^2 = u^2 + 2as
<em>S</em> = ut+ (1/2) at^2
For this question, we will be using the first one.
Third Step: Solve
<em>V </em>= 0 (the final velocity is 0, because the train stopped)
<em>U</em> = 60 (the train was going at 60 mps)
<em>T</em> = 85 seconds( 1 min and 25 sec)
0<em> </em>= 60+ 85a