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3 years ago

What’s the slope to (-5,5) (5,-4)

Mathematics

1 answer:

Lena [83]3 years ago

6 0

Answer:

Step-by-step explanation:

(-5,5)...x1 = -5 and y1 = 5

(5,-4)...x2 = 5 and y2 = -4

slope = (y2 - y1) / (x2 - x1)

slope = (-4 - 5) / (5 - (-5) = -9 / (5 + 5) = -9/10 <==

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All the place value of 12,354.897

frutty [35]

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3 years ago

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WILL GIVE BRAINLIEST!!!!

Vesna [10]

$(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =$

$= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}$

$= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}$

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3 years ago

URGENT Two numbers have a sum of 2 and a difference of -16. What are the numbers?

Firlakuza [10]

Answer:

-7 and 9!

Step-by-step explanation:

To get to the sum of 2 you add -7 and 9.

To get to the diffrence of -16 you minus -7 and 9.

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3 years ago

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Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

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3 years ago

12x^2+ 16x factor by gcf

qaws [65]

Answer:

The factor of 12x^2 + 16 is 4x (3x+4)

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2 years ago