The two angles are 155 degrees and 25 degrees
<h3><u>
Solution:</u></h3>
Given that two supplementary angles are in ratio 31 : 5
Let the first angle be 31a
Let the second angle be 5a
Two Angles are Supplementary when they add up to 180 degrees.
Therefore,
first angle + second angle = 180 degrees
<em><u>Therefore the angles are:</u></em>
first angle = 31a = 31(5) = 155 degrees
second angle = 5a = 5(5) = 25 degrees
Thus the two angles are 155 degrees and 25 degrees
Answer:
<u>(3 </u>x 6) + (2 x<u> 6)</u>
Step-by-step explanation:
So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
