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Murljashka [212]
3 years ago
9

How many significant figures are in 0.57

Chemistry
2 answers:
SashulF [63]3 years ago
7 0

Answer:

2

Explanation:

zavuch27 [327]3 years ago
4 0

Answer:

0.57

Sig Figs

2

Decimals

2

Scientific Notation

5.7 × 10-1

Words

zero point five seven

Explanation:

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If 335 g water at 35.5C loses 5750 J of heat, what is the final temperature of the water?
White raven [17]

Answer:

The final temperature is  39.58 degree Celsius

Explanation:

As we know

Q = m * c * change in temperature

Specific heat of water (c) = 4.2 joules per gram per Celsius degree

Substituting the given values we get  -

5750 = 335 * 4.2 * (X - 35.5)

X = 39.58 degree Celsius

3 0
3 years ago
CALCULATE THE VOLUME OF 16 g OF OXYGEN GAS AT S.T.P?
White raven [17]

Answer:

To calculate the volume we must first find the number of moles

Number of moles (n ) = mass / Molar mass (M)

Since oxygen is diatomic

M of oxygen = 16 × 2 = 32g/mol

n = 16 / 32 = 0.5mol

Next we use the formula

V = n × V(dm³)

where V is the volume

V(dm³) is the volume of 1 mole of a substance at s.t.p which is

22.4dm³

Volume of oxygen gas at s.t.p is

0.5 × 22.4dm³

= 11.20dm³

Hope this helps you

7 0
3 years ago
Consider 2.4 moles of a gas contained in a 4.0 L bulb at a constant temperature of 32°C. This bulb is connected to an evacuated
Luden [163]

Complete Question

The complete question is shown on the first uploaded image

Answer

a

As the valve is opened , the gas will flow into the empty container until the both containers have the same pressure

b

\Delta H = 0\ , \Delta E = 0 , q= 0 , w= 0

c

The driving force for this process is the increase in entropy this is because the movement of the internal energy of the gas into a larger volume, what this does is that it increases the amount of disorder(entropy).

Explanation

In order to obtain the parameter in the part B of the question we are first obtain the initial pressure, using the ideal gas equation  

                      P = \frac{nRT}{V}

                     P = \frac{(2.4mol)(0.0821\frac{1 atm}{K \cdot \ mol} )}{4.0L}

                         P =15 \ atm

The next thing is to obtain the new pressure of the gas , using boyle's law

              P_1V_1 = P_2V_2

                  P_2 = \frac{P_1 V_1}{V_2}

                  P_2 = \frac{(15 \ atm)(4.0L)}{24.0 L}

                  P_2 = 2.5 \ atm    

Since the this process is isothermal , the change in heat is equal to zero

                      i.e  q = 0 J

  The workdone to move  the gas to the other container is zero because the  the pressure at this second container is zero due to the fact that it is a vacuum

    i.e  w = -P_{external} \Delta V

              =-(0 \ atm) (24.0 - 4.0L)

              = 0L \cdot atm

  Since the change in heat is zero and the workdone is zero then the change in internal energy is equal to 0

     This is because the change in internal energy is equal to a summation of change in heat and the workdone

                i.e \Delta E = q + w

                            = 0J

Generally the change in enthalpy is mathematically represented as

                \Delta H = n C_p \Delta T

Since the temperature is zero this means that the change in temperature is zero , substituting this value for change in temperature into the equation for  change in enthalpy

           \Delta H = n C_p (0)

                   = 0J

 

7 0
4 years ago
ASAP PLEASEE
Agata [3.3K]

Seven diatomic elements are H₂, Cl₂, N₂, F₂, Br₂, I₂ and O₂.

<h3>Which are diatomic molecules?</h3>

Diatomic molecules are those molecules in which two atoms of same elements are present, and they are combined to attain the stability.

The seven diatomic molecules which are exist in the chemistry are:

  • Hydrogen gas (H₂)
  • Chlorine gas (Cl₂)
  • Nitrogen gas (N₂)
  • Fluorine gas (F₂)
  • Bromine gas (Br₂)
  • Iodine gas (I₂)
  • Oxygen gas (O₂)

Hence H₂, Cl₂, N₂, F₂, Br₂, I₂ and O₂ are 7 diatomic molecules.

To know more about diatomic molecules, visit the below link:
brainly.com/question/14466404

#SPJ1

7 0
2 years ago
A.) Thermal Decomposition of 2.765 g NaHCO3 yields 1.234g of a solid Na2CO3 . Calculate the theoreticial yield and percent yield
velikii [3]
2NaHCO3 -> Na2CO3 + H2O + CO2 
<span>2.765g NaHCO3/MM = moles NaHCO3 </span>
<span>moles NaHCO3 x (1 mole Na2CO3 / 2 moles NaHCO3) x MM Na2CO3 = theoretical yield of Na2CO3 </span>

<span>Percent yield is simply the actual yield/theoretical yield (x100 to put it into percentage).

MM = Molar mass (grams of substance per mol)</span>
5 0
3 years ago
Read 2 more answers
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