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Elden [556K]
3 years ago
9

How many oxygen atoms are in 2.30 g of quartz?

Chemistry
2 answers:
zzz [600]3 years ago
7 0
4.61*10^22 oxygen atoms in 2.30 quartz
marysya [2.9K]3 years ago
7 0

Answer:

4.61 * 10²² oxygen atoms

Explanation:

  • Quartz is the common name of a silicon mineral, SiO₂.
  • To solve the problem, we need to calculate the molar mass (MM) of quartz:

MM = AtomicMass of Si + 2 * AtomicMass of O

MM = 28.08 + 2 * 16

MM =  60.08 g/mol

  • Then we can calculate how many moles of quartz are in 2.30 g:

2.30 g * \frac{1mol}{60.08g} = 0.0383 mol

  • Then we use <em>Avogadro's number </em>calculate the number of oxygen atoms in 0.0383 mol of SiO₂, keeping in mind the number of O per quartz molecule:

0.0383 mol SiO₂ * \frac{2molO}{1molSiO_{2}}*\frac{6.023*10^{23}atomsO}{1molO} = 4.61 * 10²² atoms of O

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At one point in the Bike Trip described in the passage, you traveled 1 kilometer in 0.1 hours. What was your speed during that t
stealth61 [152]

Answer:

v = 10 km/h

Explanation:

Step 1: Given data

  • Distance traveled in the Bike Trip (d): 1 km
  • Time elapsed in the Bike Trip (t): 0.1 h

Step 2: Calculate the speed in the Bike Trip

The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.

v = d/t

v = 1 km/0.1 h

v = 10 km/h

The speed is 10 kilometers per hour.

7 0
3 years ago
A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 0.10 M HCl(aq) (adding HCl to NaOH). Determine which region on the titratio
Anna11 [10]

Answer:

1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.

2) The pH of the solution after adding HCl is 12.6

Explanation:

10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.

nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol

nHCl=\frac{0.10mol}{L} \times 15.0 \times 10^{-3} L=1.5 \times 10^{-3}mol

There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.

                    NaOH       +       HCl       ⇒       NaCl      +         H₂O

Initial          2.5 × 10⁻³         1.5 × 10⁻³               0                      0

Reaction    -1.5 × 10⁻³        -1.5 × 10⁻³          1.5 × 10⁻³          1.5 × 10⁻³

Final            1.0 × 10⁻³               0                 1.5 × 10⁻³          1.5 × 10⁻³

The concentration of NaOH is:

[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M

NaOH is a strong base so [OH⁻] = [NaOH].

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log 0.040 = 1.4

pH = 14 - pOH = 14 - 1.4 = 12.6

5 0
3 years ago
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ludmilkaskok [199]
1. The molar mass of Fe2(CO3)3 is 291.72 g/mol. This means that 45.6 g is equivalent to 0.156 mol. Dividing by the 0.167 L of water gives a solution of 0.936 M.
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