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netineya [11]
2 years ago
8

During takeoff, a plane goes from 0 to 50 m/s in 8s. What is its acceleration? Halos fast is it going after 5 s? How far had it

traveled by the time it reaches 50 m/s?
Physics
2 answers:
masha68 [24]2 years ago
5 0

Answer : Its acceleration is, 6.25m/s^2

The velocity after 5 s is, 31.25 m/s

The distance traveled by the time it reaches 50 m/s is, 200 m

Solution :

First we have to calculate the acceleration.

Formula used : a=\frac{\Delat v}{t}

where,

a = acceleration

v = change in velocity = 50 - 0 = 50 m/s

t = time = 8 s

Now put all he given values in the above formula, we get

a=\frac{50m/s}{8s}=6.25m/s^2

Therefore, its acceleration is, 6.25m/s^2

Now we have to calculate the velocity after 5 second.

Formula used : v=u+at

where,

v = final velocity

u = initial velocity = 0 m/s

a = acceleration = 6.25m/s^2

t = time = 5 s

Now put all the given values in the above formula, we get

v=0m/s+(6.25m/s^2)\times (5s)=31.25m/s

Therefore, the velocity after 5 s is, 31.25 m/s

Now we have to calculate the distance traveled by the time it reaches 50 m/s.

Formula used : v^2-u^2=2as

where,

s = distance traveled

Now put all the given values in the above formula, we get

(50m/s)^2-(0m/s)^2=2\times (6.25m/s^2)\times s

s=200m

Therefore, the distance traveled by the time it reaches 50 m/s is, 200 m

svlad2 [7]2 years ago
4 0
A= 50/8 m/s^2 

<span>vf=at=50/8 * 5= 250/8 m/s at t=5sec </span>

<span>time to get to 50m/s </span>
<span>50=50/8*t or t=8 seconds </span>
<span>distance=1/2 a t^2=1/2 50/8 64 </span>
<span>distance= 400 m check that.</span>
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