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Vitek1552 [10]
4 years ago
5

A 3000 n force acts on a 200 kg object what is the acceleration of the object

Physics
2 answers:
lesantik [10]4 years ago
7 0
F=ma. a= F/m = 3000/200 = 15 m/s
Virty [35]4 years ago
3 0

Explanation:

As we know that relation between force, mass and acceleration is as follows.

                              F = ma

where,    F = force

              m = mass

               a = acceleration

So, it is given that force is 3000 N and mass is 200 kg. Hence, calculate the acceleration as follows.

               F = ma

              3000 N = 200 \times a

                  a = \frac{3000}{200}

                     = 15 m/s^{2}

Thus, we can conclude that acceleration of the given object is 15 m/s^{2}.

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A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

6 0
4 years ago
A 0.0663 kg ingot of metal is heated to 241◦C
Westkost [7]

Answer:280.216j/kg°C

Explanation:

Mass of metal=0.0663kg

mass of water=0.395kg

Final temperature=27.4°C

Temperature of metal=241°C

Temperature of water=25°C

specific heat capacity of water=4186j/kg°C

0.0663xax(241-27.4)=0.395x4186x(27.4-25)

0.0663xax213.6=0.395x4186x2.4

14.16168a=3968.328

a=3968.328 ➗ 14.16168

a=280.216j/kg°C

4 0
3 years ago
using newtons law a force of 250N is applied to an object that accelerates at a rate of 5M/s2 what is the mass of the object?
AURORKA [14]

Answer:

50 kg

Explanation:

F = ma

250 N = m (5 m/s²)

m = 50 kg

7 0
3 years ago
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vichka [17]
The answer to the problem b.
8 0
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A car travels 70 km in two hours 104 km in the next 1.5 hours and then 79 km in two hours before reaching its destination what w
stiks02 [169]

Average speed = (total distance) / (total time)

Total distance = (70km + 104km + 79km) = 253 km

Total time = (2hr + 1.5hr + 2hr) = 5.5 hrs

Average speed = (253 km) / (5.5 hrs)

<em>Average speed = 46 km/hr</em>

4 0
4 years ago
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