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Vitek1552 [10]
4 years ago
5

A 3000 n force acts on a 200 kg object what is the acceleration of the object

Physics
2 answers:
lesantik [10]4 years ago
7 0
F=ma. a= F/m = 3000/200 = 15 m/s
Virty [35]4 years ago
3 0

Explanation:

As we know that relation between force, mass and acceleration is as follows.

                              F = ma

where,    F = force

              m = mass

               a = acceleration

So, it is given that force is 3000 N and mass is 200 kg. Hence, calculate the acceleration as follows.

               F = ma

              3000 N = 200 \times a

                  a = \frac{3000}{200}

                     = 15 m/s^{2}

Thus, we can conclude that acceleration of the given object is 15 m/s^{2}.

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Answer:

n = 5 approx

Explanation:

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\frac{v_1}{v} = e ( coefficient of restitution ) = \frac{1}{\sqrt{10} }

and

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h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

e = \sqrt{\frac{h_1}{6.1} }

e = \sqrt{\frac{h_2}{h_1} }

So on

e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }

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- n / 2 = log .00396

n / 2 = 2.4

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Measuring the volume of a ball that is 24cm across how can you set up an equation
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