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3 years ago

A 3000 n force acts on a 200 kg object what is the acceleration of the object

Physics

2 answers:

lesantik [10]3 years ago

7 0

F=ma. a= F/m = 3000/200 = 15 m/s

Virty [35]3 years ago

3 0

Explanation:

As we know that relation between force, mass and acceleration is as follows.

F = ma

where, F = force

m = mass

a = acceleration

So, it is given that force is 3000 N and mass is 200 kg. Hence, calculate the acceleration as follows.

F = ma

3000 N = $200 \times a$

a = $\frac{3000}{200}$

= $15 m/s^{2}$

Thus, we can conclude that acceleration of the given object is $15 m/s^{2}$ .

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3 years ago

Read 2 more answers

Objects with masses of 165 kg and a 465 kg are separated by 0.340 m. (a) Find the net gravitational force exerted by these objec

Dmitrij [34]

Answer:

(a) $F_{net}$ = 4.19 x $10^{-5}$ N, and its direction is towards $m_{2}$ .

(b) It must be placed inside a hollow shell.

Explanation:

Let, $m_{1}$ = 165 kg, $m_{2}$ = 465 kg, $m_{3}$ = 60 kg, and the distance between $m_{1}$ and $m_{2}$ is 0.340 m.

(a) Since $m_{3}$ is placed midway between $m_{1}$ and $m_{2}$ , then its distance to both masses is 0.170 m.

From the Newton's law of universal gravitation,

F = $\frac{Gm_{1}m_{2} }{r^{2} }$

Where all variables have their usual meaning.

Then,

a. $F_{net}$ = $F_{23}$ - $F_{13}$

$F_{13}$ = $\frac{6.67*10^{-11}*165*60 }{(0.17)^{2} }$

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$F_{23}$ = $\frac{6.67*10^{-11}*465*60 }{(0.17)^{2} }$

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∴ $F_{net}$ = = 6.44 x $10^{-5}$ - 2.25 x $10^{-5}$

= 4.19 x $10^{-5}$ N

The net force exerted by the two masses on the 60 kg object is 4.19 x $10^{-5}$ N.

(ii) / $F_{net}$ / = / $F_{23}$ / - / $F_{13}$ /

= 6.44 x $10^{-5}$ - 2.25 x $10^{-5}$

= 4.19 x $10^{-5}$ N

(iii) The direction of the net force is to the right i.e towards $m_{2}$ .

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3 years ago

An electron in the n = 5 level of an h atom emits a photon of wavelength 1282.17 nm. to what energy level does the electron move

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This is an interesting (read tricky!) variation of Rydberg Eqn calculation.
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Hence 1/(1282.17 ×10^-9) = 1.09737× 10^7 [1/n1^2 – 1/25^2]
Some rearranging and collecting up terms:
1 = (1282.17 ×10^-9) (1.09737× 10^7)[1/n2 -1/25]
1= 14.07[1/n^2 – 1/25]
1 =14.07/n^2 – (14.07/25)
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n = √(14.07/1.5628) = 3

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