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Vitek1552 [10]
3 years ago
5

A 3000 n force acts on a 200 kg object what is the acceleration of the object

Physics
2 answers:
lesantik [10]3 years ago
7 0
F=ma. a= F/m = 3000/200 = 15 m/s
Virty [35]3 years ago
3 0

Explanation:

As we know that relation between force, mass and acceleration is as follows.

                              F = ma

where,    F = force

              m = mass

               a = acceleration

So, it is given that force is 3000 N and mass is 200 kg. Hence, calculate the acceleration as follows.

               F = ma

              3000 N = 200 \times a

                  a = \frac{3000}{200}

                     = 15 m/s^{2}

Thus, we can conclude that acceleration of the given object is 15 m/s^{2}.

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2 years ago
A ball is thrown straight up. If the launch velocity is 15 m/s, at what SPEED will the ball return to the thrower’s hand?
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Answer:

Vf = 15 m/s

Explanation:

First we consider the upward motion of ball to find the height reached by the ball. Using 3rd equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = -9.8 m/s² (negative sign for upward motion)

h = height =?

Vf = Final Velocity = 0 m/s (Since, ball momentarily stops at highest point)

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Therefore,

2(-9.8 m/s²)h = (0 m/s)² - (15 m/s)²

h = (-225 m²/s²)/(-19.6 m/s²)

h = 11.47 m

Now, we consider downward motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height = 11.47 m

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Vi = Initial Velocity = 0 m/s

Therefore,

2(9.8 m/s²)(11.47 m) = Vf² - (0 m/s)²

Vf = √(224.812 m²/s²)

<u>Vf = 15 m/s</u>

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