The answer to your question is a<span>s described by the third of Newton's laws of motion of classical mechanics, all </span>forces<span> occur in pairs such that if one </span>object exerts<span> a </span>force<span> on another </span>object<span>, then the second </span>object exerts<span> an equal and opposite </span>reaction force<span> on the first.</span>
Answer:
Explanation:
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My answer to this question honestly is no
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Answer
given,
F₁ is horizontal = 40 N
F₂ is normal = 20 N
F₃ is parallel = 30 N
work done by
W₂ = 0 as force is acting perpendicular to the direction of motion.
as the motion moved to 0.8 cm
W₃ = F₃ x d
W₃ = 30 x 0.8
W₃ = 24 J
W₁ = F₁ x d
W₁ = F₁ cos ∅ x d
W₁ = 40 cos 30⁰ x 0.8
W₁ = 27.21 J
