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Zigmanuir [339]
3 years ago
8

12. The bond formed when two atoms share a pair of electrons is called a

Physics
1 answer:
givi [52]3 years ago
4 0

Answer:A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

Explanation:

You might be interested in
How could you record the number 4000 and report 2 significant figures?
yawa3891 [41]

Explanation:

Write in scientific notation.

4000 = 4.0×10³

5 0
3 years ago
Question #5: Explain how a reflecting telescope is different from a refracting telescope. List the two different types of reflec
Anni [7]

The main component in a reflecting telescope is a mirror where the light will bounce off and is then focused into a smaller area. In contrast, a refracting telescope uses lenses that focus the light as it travels towards the other end.

Two different types of reflecting telescopes are:

1.Cassegrain reflector

2.Newtonian telescope

Explanation:

  • The distinction between the two is in how they manipulate the incoming light in order to magnify the image. The main component in a reflecting telescope is a mirror where the light will bounce off and is then focused into a smaller area.
  • Key advantage of reflecting telescopes is how big you can make them. With lenses, the maximum size is limited to about one meter, largely because of the problems stated above as well as the skyrocketing costs.
  • The Newtonian telescope, also called the Newtonian reflector, is a type of reflecting telescope invented Sir Isaac Newton, using a concave primary mirror and a flat diagonal secondary mirror. The Newtonian telescope's simple design has made it very popular with amateur telescope makers.
  • The Cassegrain reflector is a combination of a primary concave mirror and a secondary convex mirror, often used in optical telescopes and radio antennas, the main characteristic being that the optical path folds back onto itself, relative to the optical system's primary mirror entrance aperture.

6 0
3 years ago
When some stars use up their fuel, they undergo a catastrophic explosion called a supernova. This explosion blows much or all of
algol13

Answer:

0.0768 revolutions per day

Explanation:

R = Radius

\omega = Angular velocity

As the mass is conserved the angular momentum is conserved

I_1\omega_1=I_2\omega_2\\\Rightarrow \frac{I_1}{I_2}=\frac{\omega_2}{\omega_1}

Moment of intertia for solid sphere

I_1=\frac{2}{5}MR^2\\\Rightarrow I_1=0.4MR^2

Moment of intertia for hollow sphere

I_2=\frac{2}{3}M(4.3R)^2\\\Rightarrow I_2=12.327MR^2

Dividing the moment of inertia

\frac{I_1}{I_1}=\frac{0.4MR^2}{12.327MR^2}\\\Rightarrow \frac{I_1}{I_2}=0.032

From the first equation

\omega_2=\omega_1\frac{I_1}{I_2}\\\Rightarrow \omega_2=2.4\times 0.032\\\Rightarrow \omega_2=0.0768\ rev\day

The angular velocity, in revolutions per day, of the expanding supernova shell is 0.0768 revolutions per day

8 0
3 years ago
PLEASE HELPPPP!!!!!!!!!!
son4ous [18]

Answer:

I think its B

Explanation:

5 0
3 years ago
Read 2 more answers
Three charges, qA is +6.0 μC, qB is –5.0 μC, and qc is +6.0 μC, are located at the corners of a square with each side length at
lesya [120]

The net electric field at point D is determined as 3.95 x 10⁷ N/C.

<h3>Electric field at D due to charge A</h3>

E = kq/r²

where;

  • r is the distance between A and D
  • q is charge A

E(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(AD) = 2.16 x 10⁷ i N/C

<h3>Electric field at D due to charge B</h3>

E = kq/r²

where;

  • r is the distance between A and B
  • q is charge B

r² = 5²  + 5²

r² = 50

r = √50

r = 7.07 cm

E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)

E(BD) = 9 x 10⁶ N/C

in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i  N/C

in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j  N/C

<h3>Electric field at D due to charge C</h3>

E = kq/r²

where;

  • r is the distance between C and D
  • q is charge C

E(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(CD) = 2.16 x 10⁷ j N/C

<h3>Net electric field in x direction</h3>

Ei = 2.16 x 10⁷ i N/C  + 6.36 x 10⁶ i  N/C

Ei = 2.796 x 10⁷ i N/C

<h3>Net electric field in y direction</h3>

Ej = 2.16 x 10⁷ j N/C  + 6.36 x 10⁶j  N/C

Ej = 2.796 x 10⁷ j N/C

<h3>Resultant electric field at D</h3>

E = √Ei² + Ej²

E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]

E = 3.95 x 10⁷ N/C

Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

7 0
2 years ago
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