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nydimaria [60]
3 years ago
9

A long, straight solenoid has 800 turns. when the current in the solenoid is 2.90 a, the average flux through each turn of the s

olenoid is 3.25 * 10-3 wb. what must be the magnitude of the rate of change of the current in order for the self-induced emf to equal 6.20 mv?
Physics
1 answer:
tresset_1 [31]3 years ago
4 0
It has to be the right answer for it to be correct
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Answer:

option B

Explanation:

we know,

Force between two charge is calculated by

F = \dfrac{kq_1q_2}{r^2}

r is the distance between the two charges

k is Coulomb constant.

give two small object with charge Q

now, Force

F = \dfrac{kQQ}{r^2}......(1)

now,

New force if another charge is equal to 4 Q

F' = \dfrac{kQ(4Q)}{r^2}

F' = 4\dfrac{kQQ}{r^2}

now from equation 1

F' = 4 F

Hence, the correct answer is option B

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The figure above shows the net force exerted on an object as a function of the position of the object. The object starts from re
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Answer:

0.06 Kg

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Net Force (F) = 3 N

Mass (m) =?

Next, we shall determine the acceleration of the object. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Acceleration (a) =?

v² = u² + 2as

3² = 0² + (2 × a × 0.09)

9 = 0 + 0.18a

9 = 0.18a

Divide both side by 0.18

a = 9 / 0.18

a = 50 m/s²

Finally, we shall determine the mass of the object. This can be obtained as follow:

Net Force (F) = 3 N

Acceleration (a) = 50 N

Mass (m) =?

F = ma

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5 0
2 years ago
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