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nydimaria [60]
3 years ago
9

A long, straight solenoid has 800 turns. when the current in the solenoid is 2.90 a, the average flux through each turn of the s

olenoid is 3.25 * 10-3 wb. what must be the magnitude of the rate of change of the current in order for the self-induced emf to equal 6.20 mv?
Physics
1 answer:
tresset_1 [31]3 years ago
4 0
It has to be the right answer for it to be correct
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Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

F=k\frac{q_1 q_2}{r^2}

where

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r is the separation between the charges

In this problem, we have:

q_1=4.5\mu C=4.5\cdot 10^{-6}C is the magnitude of the 1st charge

q_2=2.8\mu C=2.8\cdot 10^{-6}C is the magnitude of the 2nd charge

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Therefore, the magnitude of the electric force is:

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So, the closest answer is

A) 181.24 N

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4 years ago
A wave that can travel with or without a medium is called a(n)
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Answer:

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Answer:

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