I can't see that cube from here.
But if the length of the side of the cube is ' K ' units,
then the surface area of the cube is 6K² units², and
the volume of the cube is K³ units³.
The ratio of the surface area to the volume is
(6K² units²) / (K³ units³) = (6) / (K units) .
So for example, if the side of the cube is 2 inches, then
the ratio of surface area to volume is "3 per inch".
That's the answer. I did the whole thing in order to earn
the points, but I don't expect you to understand much of it,
because I see from your username that you suck at math.
I'm sorry you decided that. Now that you've put up the
brick wall, it'll be even harder for any math to find its way
in there, and you'll miss out on a lot of the fun.
Data:
h = 2m
m = 45 Kg
PE = ? (Joule)
Adopting, gravity (g) ≈ <span>9,8 m/s²
</span>
Formula:
Solving:
Answer:
<span>
The sled's potential energy is 882 Joules</span>
The new magnitude of the force of attraction will be 6 times the original force of attraction
<h3>How to determine the initial force </h3>
- Mass 1 = m₁
- Mass 2 = m₂
- Gravitational constant = G
- Distance apart = r
- Initial force (F₁) = ?
F = Gm₁m₂ / r²
F₁ = Gm₁m₂ / r²
<h3>How to determine the new force </h3>
- Mass 1 = 2m₁
- Mass 2 = 3m₂
- Gravitational constant = G
- Distance apart (r) = r
- New force (F₂) =?
F = Gm₁m₂ / r²
F₂ = G × 2m₁ × 3m₂ / r²
F₂ = 6Gm₁m₂ / r²
But
F₁ = Gm₁m₂ / r²
Therefore
F₂ = 6Gm₁m₂ / r²
F₂ = 6F₁
Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction
Learn more about gravitational force:
brainly.com/question/21500344
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A particle with charge -40.0nC is on the x axis at the point with coordinate x=0 . A second particle, with charge -20.0 nC, is on the x axis at x=0.500 m.
No, there is no point at a finite distance where the electric potential is zero.
Hence, Option D) is correct.
What is electric potential?
Electric potential is the capacity for doing work. In the electrical case, a charge will exert a force on some other charge and the potential energy arises. For example, if a positive charge Q is fixed at some point in space, any other positive charge when brought close to it will experience a repulsive force and will therefore have potential energy.
It is also defined as the amount of work required to move a unit charge from a reference point to a specific point against an electric field.
To learn more about electric potential, refer to:
brainly.com/question/15764612
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