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Over [174]
2 years ago
15

I kinda don’t know how to solve this I need help.

Physics
1 answer:
NemiM [27]2 years ago
7 0

Answer:

the answer is 11 N left

Explanation:

there is more force being applied in the direction left, so the ball will move left. to find the net force that the ball will move in that direction subtract the force being applied in the opposite direction. so, 16N-5N=11N. your answer in 11 N left.

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2.
Shkiper50 [21]

Answer:

the balloon is filled with the 8.5 litre of helium. temperature is 294 kelvin.

party starts at 4 p.m.

the temperature rises 305 kelvin.

the new volume = 4 litres

5 0
3 years ago
A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
Step2247 [10]

The final volume of the gas is 144.25 L

Explanation:

For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by

W=p\Delta V = p(V_f - V_i)

where

p is the pressure of the gas

V_i is the initial volume

V_f is the final volume

For the gas in the cylinder in this problem,

p = 2.00 atm

V_i = 0.250 L

And we also know the work done,

W = 288 J

So we can solve the equation for V_f, the final volume:

V_f = V_i + \frac{W}{p}=0.250 + \frac{288}{2.00}=144.25 L

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

7 0
3 years ago
2 QUESTIONS HELP PLZ...:/
algol [13]
The first one is: head
Second one is: 10 trillion km
5 0
3 years ago
A 167-? resistor and a 114-? resistor are both connected in parallel across a power supply. If the potential drop across the 167
Troyanec [42]
19-? Is the exact p.d across the 114-?resistor.
Current will different
But p.d will same in parallel circuit .
7 0
3 years ago
The block slides on a horizontal frictionless surface. The block has a mass of 1.0kg and is pushed 5.0N at 45°. What is the magn
Firlakuza [10]

Answer:

3.5\:\mathrm{m/s^2}

Explanation:

Newton's 2nd law is given as \Sigma F = ma.

To find the acceleration in the horizontal direction, you need the horizontal component of the force being applied.

Using trigonometry to find the horizontal component of the force:

\cos 45^{\circ}=\frac{x}{5},\\\frac{\sqrt{2}}{{2}}=\frac{x}{5},\\x=\frac{5\sqrt{2}}{2}

Use this horizontal component of the force to solve for for the acceleration of the object:

\frac{5\sqrt{2}}{2}=1.0\cdot a,\\a=\frac{5\sqrt{2}}{2}\approx \boxed{3.5\:\mathrm{m/s^2}}

8 0
2 years ago
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