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Over [174]
2 years ago
15

I kinda don’t know how to solve this I need help.

Physics
1 answer:
NemiM [27]2 years ago
7 0

Answer:

the answer is 11 N left

Explanation:

there is more force being applied in the direction left, so the ball will move left. to find the net force that the ball will move in that direction subtract the force being applied in the opposite direction. so, 16N-5N=11N. your answer in 11 N left.

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Which person is weightless?
ahrayia [7]

Answer: Option (b) is the correct answer.

Explanation:

The force of gravity acting on an object helps in determining the weight of an object. But a place where there will be no gravity or have zero gravitational pull then it means the person will be weightless.

For example, force of gravity on moon is zero which means any object or person on moon will be weightless.

On the other hand, when a child is in the air as she plays on a trampoline then it means gravitational pull form the earth is acting on it. So, it will definitely has some weight.

Similarly, a scuba diver exploring a deep-sea wreck is under the ground where there will be force of gravity. Hence, it will also have some weight.

Thus, we can conclude that an astronaut on the Moon is the person who is weightless.

7 0
3 years ago
Automotive technology
viktelen [127]

lol what is this question

5 0
2 years ago
A stone is thrown towards a wall with an initial velocity of v0=19m/s and an angle = 71 with the horizontal, as illustrated in t
HACTEHA [7]

Answer:

(a) 2.85 m

(b) 16.5 m

(c) 21.7 m

(d) 22.7 m

Explanation:

Given:

v₀ₓ = 19 cos 71° m/s

v₀ᵧ = 19 sin 71° m/s

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

(a) Find Δy when t = 3.5 s.

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (19 sin 71° m/s) (3.5 s) + ½ (-9.8 m/s²) (3.5 s)²

Δy = 2.85 m

(b) Find Δy when vᵧ = 0 m/s.

vᵧ² = v₀ᵧ² + 2 aᵧ Δy

(0 m/s)² = (19 sin 71° m/s)² + 2 (-9.8 m/s²) Δy

Δy = 16.5 m

(c) Find Δx when t = 3.5 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.5 s) + ½ (0 m/s²) (3.5 s)²

Δx = 21.7 m

(d) Find Δx when Δy = 0 m.

First, find t when Δy = 0 m.

Δy = v₀ᵧ t + ½ aᵧ t²

(0 m) = (19 sin 71° m/s) t + ½ (-9.8 m/s²) t²

0 = t (18.0 − 4.9 t)

t = 3.67

Next, find Δx when t = 3.67 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.67 s) + ½ (0 m/s²) (3.67 s)²

Δx = 22.7 m

7 0
3 years ago
A bar of gold has a temperature of 31°C, and a bar of aluminum has a
Katarina [22]
Different dense matters
3 0
3 years ago
What step of the rock cycle happens as the sea stacks are broken down
lesya692 [45]

D. Weathering

The six steps of the rock cycle includes Weathering and Erosion, Transportation, Deposition, Compaction and Cementation. Metamorphism, Rock Melting.

Deposition is the process where rock particles sink at the rivers and become sediment.

Weathering is the process by which wind and water breaks down igneous, sedimentary, and metamorphic rocks. The process refers to large rocks broken down into smaller pieces and the broken off particles stay in the area.  


5 0
3 years ago
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