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Lemur [1.5K]
3 years ago
5

Are Molar Mass and Molecular Mass the same thing? If they are different, then why are they used interchangeably?

Chemistry
2 answers:
JulsSmile [24]3 years ago
7 0
The molar mass of one mole of whatever substance/element you have while the molecular mass is the mass of one molecule. They are used differently according to the measurements and base on their units. I hope you are satisfied with my answer.
exis [7]3 years ago
4 0

At this point there are two answers:  one says that there is no difference, except for the units;  the molecular weight (MW) is the mass of one molecule, while a molar mass is the mass of a mole (6.02 x 10 ^ 23) of molecules.

While in certain contexts both statements can be shown to be true, I'm not sure these answers really provide you with the insight you're looking for.

So, we'll look at your question from a different perspective.   Take a real example, something simple like water.  Water has a nominal MW of 18 (so we'll use nominal precision for simplicity, instead of the 4-places often used for these types of calculations).

The MW of water (formula = H2O) is the weight of one atom of oxygen, which = 16 amu [8-neutrons at 1 amu each plus 8 protons at 1 amu each = 16 amu), plus two atoms of hydrogen, at 1 proton (1 amu) each.  Normal everyday hydrogen has no neutrons.  So for H2O, we have a total molecular weight of 18 amu.

From the CRC reference book we find that one amu weighs 1.66 x 10 ^--24 grams.  Multiplying the two and in keeping with the two units of precision we're working with, one molecule of water has a mass of  29.8 x 10^-24g, or [3.0 x 10 ^ -23 g] per molecule of water.

A Mole is simply Avagadro's number (6.02 x 10 ^ 23) of anything... protons, baseballs, whatever.  The term Molar Mass in chemistry refers to the mass of a mole of molecules.  So in this case a molar mass of water molecules is Avagadro's number of them, the mass therefore being [6.02 x 10 ^ 23] x 3.0 x 10 ^ -23 g/ molecule] =  18.0 g

Summarizing:

Molecular Weight is the weight given in amu of an atom or molecule.  For H2O, the MW is 18 amu or 3.0 x 10 ^ -23 g.

Molar Weight is the weight, usually in grams of 6.02 x 10 ^ 23 measurements which happens to be equal to the MW of the molecule (or atomic wt. of the atom) , and for water is 18.0 g.

So, while MW and molar weight are related, their absolute values are magnitudes apart.

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Answer:

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B.  Charles' Law

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An air bag inflates due to the decomposition of sodium azide or NaN₃ to completely fill the bag with nitrogen gas which is an example of Boyle's law, which states that the pressure of a given mass of gas is inversely proportional to its volume, hence due to the estricted volume of the airbag, the pressure of the nitrogen gas in the bag increses protecting the occupants of a cr from injuries in a crash

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determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

<h2 />

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

#SPJ4

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