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AURORKA [14]
3 years ago
7

Atoms are incredibly small and we cannot see them, even with very powerful microscopes. If we cannot see them, then how do we kn

ow they are there?
Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
3 0
Albert Einstein showed in one of his papers in 1905 that Brownian motion could be explained by assuming that matter is made up of tiny particles. His paper predicted how the motion should look like and also allowed for the calculation of the mass of a single molecule. Current evidence includes: 1. Individual ions (atoms with an electric charge) can be manipulated using electric and magnetic fields. 2. Elevation maps can now be made that show bumps caused by individual atoms.
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How many grams of CO would be required to generate 635 g CO2
vivado [14]

The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g

<h3>Stoichiometric problem</h3>

First, let us get the equation of the reaction:

2CO + O_2 -- > 2CO_2

From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.

635 g of CO2 is to be generated.

Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles

Thus, the equivalent mole of CO required will also be 14.43 moles.

Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g

Hence, 404.14 g of CO will be required to produce 635 g of CO2

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

7 0
2 years ago
What is the molarity of a solution containing 17.0g of nh3 in 2.0 L of solution?
liq [111]
To find molarity use the following formula

molarity= moles/ liters

first, we need to calculate the moles using the grams of NH₃. remember to convert grams to moles, you need the molar mass of the molecule which you can determine by adding the mass of each atom

molar mass of NH₃ = 14.0 + (3 x 1.01)= 17.03 g/ mol

now, let convert grams to moles

17.0 g (1 mol/ 17.03 grams)= .998 moles NH₃

now, we can plug in these values to solve for molarity

molarity= 0.998 mol/ 2.0 Liters= 0.50 M (the answer is a)
8 0
3 years ago
PLEASEE HELPPP ME WITH NUMBER 5!!!!!!!
riadik2000 [5.3K]

Answer:

hi dont report me we are friends can i get brainliest plzz?

Explanation:

5 0
3 years ago
You need to determine the mass of an aqueous solution. You determine the mass of your 10.0 mL graduated cylinder to be 23.731 g.
Amanda [17]

Answer: 0.86g/mL

Explanation:

Mass of empty cylinder = 23.731g

Mass of cylinder + liquid = 26.414g

Mass of the liquid = 26.414 — 23.731

= 2.683g

Volume of the liquid = 3.12mL

Density = Mass / volume

Density = 2.683g / 3.12mL

Density = 0.86g/mL

3 0
3 years ago
7. Some of the following sublevels do not exist. Cross out the ones that are not real.
zubka84 [21]

Answer:

1f 3f 5g 1p 2d

Explanation:

There is only 4f and 5f orbitals.

G is not an orbital.

P orbital starts with 2p

D orbital starts with 3d

7 0
3 years ago
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