Answer: Freezing point of a solution will be 
Explanation:
Depression in freezing point is given by:

= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
= freezing point constant = 
m= molality

Weight of solvent (benzene)= 1480 g =1.48 kg
Molar mass of solute (octane) = 114.0 g/mol
Mass of solute (octane) = 220 g



Thus the freezing point of a solution will be 
The molarity of a solution is the number of moles of a substance in one liter of that substance.
The molar mass of ammonium sulfate (NH4)2SO4 is 132.14 grams/mole
Calculate the moles of ammonium sulfate:
(4.50 grams)/(132.14 grams/mole) = 0.0341 moles of ammonium sulfate
convert mL to Liters 250. mL becomes 0.250 liters
Take the number of moles over the number of liters
0.0341 moles / 0.250 liters = 0.136 molar or 0.136M = molarity of the solution
Paid sponsorship by a company
a person running a car parked in a driveway
Explanation:
A person running a car parked in a driveway is an example of translational kinetic energy.
Translational motion is the movement of body along a straight path.
Translational kinetic energy refers to the energy of a body moving along a straight path.
- It is function of the mass and velocity of the moving body.
- The motion of train on its track is an example of this form of energy
- A fired bullet, falling object all experience translational kinetic energy.
learn more:
Translational kinetic energy brainly.com/question/9924094
#learnwithBrainly