Given:
257J of heat
5500g of mercury
increase by 5.5
degrees Celsius
Required:
Specific heat of
mercury
Solution:
H
= mCpT
257J = (5500g of
mercury) Cp (5.5 degrees Celsius)
Cp = 8.5 x 10^-3
Joules per gram per degree Celsius
Answer:
Explanation:
1) Valence electrons
2) Electrons
3) 2 electrons on K-shell
4) 8 electrons on L-Shell
5) 18 electrons on M-shell
6) nucleus
7) Proton
8) neutron
9) principal energy level
10) atomic number
11) symbol of the atom
12) name of the atom
13) atomic mass
Answer:
1 A
3 main types of bond are
Ionic bond ( formed due to complete transfer of electron between atoms(
Covalent bond ( formed by mutual sharing of electron)
Metalic bond ( present in the metals due to mobile electrons)
1 B bond in CaO is ionic bond formation in attached image
1 C hydrogen bond with nitrogen is covelent NH3 ammonia is formed because a bond between two non metals is expected to be covalent
More their electronegativity difference between hydrogen and nitrogen is less than 1.7 that makes it covalent
Explanation:
The section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summary is They can also be moved or killed if they cause trouble.
<h3>Are beavers a threat to humans?</h3>
Beavers are not to be creature which are not dangerous if left to be alone. But, they will often confront any threat when they are trapped or cornered, and thus a beaver will attack a human.
Hence, The section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summary is They can also be moved or killed if they cause trouble.
Learn more about Beavers from
brainly.com/question/26756213
#SPJ1
According to the balanced equation of the reaction:
2C2H2 + 5O2 → 4CO2 + 2H2O
So we can mention all as liters,
A) as we see that 2 liters of C2H2 react with 5 liters of oxygen to produce 4 liters of CO4 and 2 liters of H2O
So, when we have 75L of CO2
and when we have 2 L of C2H2 reacts and gives 4 L of CO2
2C2H2 → 4CO2
∴ The volume of C2H2 required is:
= 75L / 2
= 37.5 L
B) and, when we have 75 L of CO2
and 4CO2 → 2H2O
∴ the volume of H2O required is:
= 75 L /2
= 37.5 L
C) and from the balanced equation and by the same way:
when 5 liters O2 reacts to give 4 liters of CO2
and we have 75 L of CO2:
5 O2 → 4 CO2
?? ← 75 L
∴ the volume of O2 required is:
= 75 *(5/4)
= 93.75 L
D) about the using of the number of moles the answer is:
no, there is no need to find the number of moles as we called everything in the balanced equation by liters and use it as a liter unit to get the volume, without the need to get the number of moles.
