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RideAnS [48]
3 years ago
8

If you have 6 moles of reactant A and excess of B and C, how much product E would be formed

Chemistry
1 answer:
pychu [463]3 years ago
3 0
B and C are in excess so amount of E will be determined by A. 

Amount of product is determined by limiting reagents - Always.

Hence 6 moles of E will be formed.

Hope this helps!
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The number 875000 written in scientific notation would be
babymother [125]

Answer:

8.75 x 10^5

Explanation:

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What elements are found in the compound represented in the diagram
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 hydrogen and carbon, hope that helped


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why is it essential to know the water temperature in this experiment- to find the vapor pressure of the water
Oksi-84 [34.3K]

Answer:

Vapour pressure of a liquid varies with temperature

Explanation:

The vapour pressure of any liquid is directly proportional to the temperature of the liquid. This implies that, as the temperature of the liquid increases, the vapour pressure increases likewise and vice versa.

Since the vapour pressure of liquid varies with the temperature of the liquid, it is essential to know the water temperature in the experiment to determine the vapour pressure of water.

5 0
3 years ago
Determine the formula weight of caffeine, C₈H₁₀N₄O₂. Provide an answer to two decimal places.
arlik [135]

Let's find

\\ \tt\hookrightarrow C_8H_10N_4O_2

  • We need accurate mass

\\ \tt\hookrightarrow 8(12.011)+10(1.007)+4(14.006)+2(16.0)

\\ \tt\hookrightarrow 96.088+10.07+56.024+32.0

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5 0
2 years ago
Read 2 more answers
0.785 moles of N2,fill a balloon at 1.5 atm and 301 K.<br> What is the volume of the balloon?
Tcecarenko [31]

Answer:

V = 12.93 L

Explanation:

Given data:

Number of moles = 0.785 mol

Pressure of balloon = 1.5 atm

Temperature = 301 K

Volume of balloon = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

V = nRT/P

V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm

V = 19.4 L /1.5

V = 12.93 L

7 0
3 years ago
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