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statuscvo [17]
3 years ago
11

Two points along a wire are labeled Xand Y. The current is measured to be iXY= –3A.The reference direction of iXY is defined by

double-subscript notation. a. In which direction are electrons flowing? From X to Y, or from Y to X? b. How much charge (in coulombs) passes through a cross section of the wire in 5 seconds?
Engineering
1 answer:
klasskru [66]3 years ago
4 0

Answer:

a. From Y to X

b. q = 15 C

Explanation:

a.

When current is denoted by double subscript, it is interpreted as traveling from 1st subscript to the second, when the value of current is positive. On the other hand, if the value of current is negative, then it means that the current is traveling from 2nd subscript to the 1st subscript. Since, the value of current is negative in the given question, therefore, it means that the current is traveling from 2nd subscript to the 1st subscript. Hence the direction of current or the flow of electrons is:

<u>From Y to X</u>

<u></u>

b.

Using the following formula of current:

I = q/t

where,

I = Current (Absolute Value) = 3  A

q = amount of charge = ?

t = time taken = 5 s

Therefore,

3 A = q/5 s

q = (3 A)(5 s)

<u>q = 15 C</u>

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Len [333]

Answer:

forwarder

Explanation:

8 0
3 years ago
Set up the following characteristic equations in the form suited to Evanss root-locus method. Give L(s), a(s), and b(s) and the
Sunny_sXe [5.5K]

Answer:

attached below is the detailed solution and answers

Explanation:

Attached below is the detailed solution

C(iii) : versus the parameter C

The parameter C is centered in a nonlinear equation, therefore the standard locus will not apply hence when you use a polynomial solver the roots gotten would be plotted against C

4 0
3 years ago
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210
Naily [24]

Answer:

1.2727 stokes

Explanation:

specific gravity of fluid A = 1.65

Dynamic viscosity = 210 centipoise

<u>Calculate the kinematic viscosity of Fluid A </u>

First step : determine the density of fluid A

Pa = Pw * Specific gravity =  1000 * 1.65 = 1650 kg/m^3

next : convert dynamic viscosity to kg/m-s

210 centipoise = 0.21 kg/m-s

Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A

                                            = 0.21 / 1650 = 1.2727 * 10^-4 m^2/sec

Convert to stokes = 1.2727 stokes

4 0
3 years ago
Fast plz-The mirror check may involve ______________.
barxatty [35]

Answer:

Realigning the mirror

Explanation:

mirrors should be aligned to minimize blind spots, not look at the tires.

6 0
3 years ago
A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
NISA [10]

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

6 0
3 years ago
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